Electric Field due to a Charged Disk.

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To find the electric field due to a charged disk with maximum charge at the center and decreasing towards the edges, one must first define the surface charge density as a function of the radial distance from the center. The discussion emphasizes the importance of showing attempts at solving the problem to receive assistance. It suggests starting with the surface charge density to formulate the electric field equations. The user is encouraged to explore the relationship between charge distribution and electric field strength along the axis of the disk. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


Find the electric field due to a Charged Disk at a distance of "d" which is in the disk's axis direction. The charge has it's maximum value at disk's center and decreases towards the edges.

I have the solution for uniformly charged disk but I can't figured it out for the situation above. Thank you.

Homework Equations





The Attempt at a Solution


http://img78.imageshack.us/img78/2523/23735598xe1.jpg
http://g.imageshack.us/img78/23735598xe1.jpg/1/
 
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Any answers?
 
What have you tried so far? No one would help you if you don't show any attempt. Start by writing the surface charge density of the disk in terms of r, the radial distance from the disk centre to any given point on the disk.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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