Electric Field due to Capacitor Plates

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SUMMARY

The discussion focuses on calculating the electric field between two parallel capacitor plates with a uniform charge density J. The derived formula for the electric field at a point x from the positive plate, when a potential difference V is applied, is given as V/d - J*(d-2x)/(2*epsilon_o). The participants clarify that the electric field produced by an infinite plate is (charge density)/2*epsilon_o, and the net electric field is the difference between the field without the charge distribution and the induced field from the charge distribution.

PREREQUISITES
  • Understanding of electric fields and capacitors
  • Familiarity with the concept of charge density
  • Knowledge of potential difference in electrical circuits
  • Basic grasp of Gauss's law and its application
NEXT STEPS
  • Study the derivation of electric fields from infinite plane sheets of charge
  • Learn about the application of Gauss's law in capacitor systems
  • Explore the relationship between electric field and potential difference in capacitors
  • Investigate the effects of different charge distributions on electric fields
USEFUL FOR

Students studying electromagnetism, electrical engineers, and anyone interested in understanding the behavior of electric fields in capacitor systems.

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Homework Statement



A capacitor consists of two plane parallel plates, separated by a distance d. The space in between is filled with a uniform charge density J. Find the electric field at a point x away from the positive plate when a potential difference V is applied.

Homework Equations





The Attempt at a Solution



I am finding it difficult to locate this point in the setup -- as in, whether it is located outside to plates or inside. I am assuming that it is the latter. I know that the field produced by an infinite plate is (charge density)/2*epsilon_o, but none of my calculations give me something that matches the answer, which happens to be:

V/d - J*(d-2x)/(2*epsilon_o)


Any help would be great.
 
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There is a uniform charge distribution (which probably means the distribution is not a conductor) between the capacitor plates. Thus, the net electric field between the plates is E = E0 - Eind. E0 would be the electric field without the charge distribution in between (which probably correlates to the V/d in the expression) and Eind is the electric field induced by the charge distribution.
 

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