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lavesh
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The volume charge density of spherical shell varies as ρ=-kr.If we have to calculate electric filed using gauss's law, can we treat as E. dA as E(dA) as there is azimuthal symmitry
An electric field is a force field that surrounds a charged object and exerts a force on other charged particles within its range. In the case of a non-uniformly charged spherical shell, the electric field is not constant throughout the shell and varies depending on the distance from the center of the shell.
The electric field at any point outside of the shell is calculated using the equation E = kQ/r^2, where k is the Coulomb's constant, Q is the total charge on the shell, and r is the distance from the center of the shell to the point. However, for points inside the shell, the electric field is zero.
As you move closer to the center of the shell, the electric field decreases. This is because the distance between the point and the charged particles on the shell decreases, resulting in a smaller force being exerted on the point by the charged particles.
Yes, the electric field can be negative for points inside the shell. This means that the force exerted on a charged particle at that point will be in the opposite direction of the electric field, towards the center of the shell.
A uniformly charged spherical shell has a constant charge density throughout the shell, resulting in a constant electric field at all points outside the shell. On the other hand, a non-uniformly charged spherical shell has a varying charge density, resulting in a non-constant electric field at different points outside the shell.