Electric field due to point charge

  • Thread starter whaler_pr
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Homework Statement


what is the magnitude or a point charge whose electric field 50cm away has the magnitude 2nc?


Homework Equations


E=1/4pi.epsilon sub zero q absolute/r sqrt2
1/4pi.epsilon sub zero=8.99x10sqrt9

The Attempt at a Solution


that gives me 71.92 and my solution in the book says 56pC am I wrong?
 

Answers and Replies

  • #2
gneill
Mentor
20,875
2,838
Yup, you're wrong :smile: The book's answer looks good.

Your formulas look a little odd. The field due to a point charge q at distance r is given by:

[tex] E = \frac{1}{4 \pi \epsilon_0} \frac{q}{r^2} [/tex]

Often the initial constant constants are rolled into a single one, k, so that

[tex] E = k \frac{q}{r^2} [/tex]

where k = 8.988 x 109 m/F
 

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