Electric Field Energy Density: Plates of Q & A

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SUMMARY

The discussion focuses on calculating the energy density of the electric field between two large non-conducting plates with equal but opposite charges of Q = 75 microC and surface area A = 0.025 m². The correct energy density is derived using the formula ω = W / V = E / (Ad), where W is energy, V is volume, and d is the distance between the plates. Participants express uncertainty regarding the teacher's provided answer of 1.7E+7 J/m³, suggesting that the actual computed energy density is 5.085E+5 J/m³, contingent upon knowing the distance between the plates.

PREREQUISITES
  • Understanding of electric field concepts and energy density
  • Familiarity with capacitor equations, specifically C = ε0A/d
  • Knowledge of energy calculations in electrostatics, W = Q²/2C
  • Basic algebra for manipulating equations and solving for variables
NEXT STEPS
  • Research the derivation of energy density formulas in electrostatics
  • Study the relationship between charge, capacitance, and energy in capacitors
  • Learn about the role of distance between plates in electric field calculations
  • Explore common pitfalls in solving electrostatic problems and how to avoid them
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Students studying electromagnetism, physics educators seeking to clarify concepts, and anyone involved in solving electrostatic problems related to capacitors and electric fields.

justin15501
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Homework Statement


Two large non-conducting plates of surface area A=.025m^2 carry equal but opposite charges Q = 75microC. What is the energy density of the electric field between the two plates.

Homework Equations


I wrote the equations on my attempt. This was a multiple choice problem and the correct answer he gave us was 1.7*10^7 but he's been wrong before.

The Attempt at a Solution


316fbdf3df98834d648106f0d95a8bd5.png

Any help is appreciated!
 
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Try again. A=.025 The rest looks correct.
 
Charles Link said:
Try again. A=.025 The rest looks correct.
The new answer I get is 508475 instead of 5085. I feel like I may be using a wrong equation or something? My teacher didn't really lecture on energy density at all so I'm a bit uncertain.
 
justin15501 said:
The new answer I get is 508475 instead of 5085. I feel like I may be using a wrong equation or something? My teacher didn't really lecture on energy density at all so I'm a bit uncertain.
I think you got the rest correct. I think your teacher's answer of 1.7E+7 may be incorrect.
 
Last edited:
Charles Link said:
I think you got the rest correct. I think your teacher's answer of 1.7E+7 may be incorrect.
My answer isn't even one of the multiple choices?
 
What is the distance between plates?
 
Energy density is
ω = W / V = E / (Ad)
where W - energy, V - volume, d - distance between the plates.

Capacity of the system (actually, we consider a capacitor)
C = ε0A/d

Energy
W = Q2/2С

Hope, it is enough to find the solution.
 
Irene Kaminkowa said:
What is the distance between plates?
Irene Kaminkowa said:
Energy density is
ω = W / V = E / (Ad)
where W - energy, V - volume, d - distance between the plates.

Capacity of the system (actually, we consider a capacitor)
C = ε0A/d

Energy
W = Q2/2С

Hope, it is enough to find the solution.
The problem doesn't say the distance between the plates.
 
justin15501 said:
The problem doesn't say the distance between the plates.
But have it in your mind.
Derive the final formula.
 
  • #10
@justin15501 Please let us know if your teacher agrees with your answer. I do think you computed it correctly.
 
  • #11
My answer is
5.085⋅105 J/m3?

Regards to your teacher )
 
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  • #12
Charles Link said:
@justin15501 Please let us know if your teacher agrees with your answer. I do think you computed it correctly.
Irene Kaminkowa said:
My answer is
5.085⋅105 J/m3?

Regards to your teacher )
Well the way it works is my professor goes over this packet of problems (including this one) the day before the exam and leaves us to figure out the questions we got wrong on our own. And there's 165 questions in this packet. It's not a very ideal situation. If I get something wrong, it's not like I can go to him for help. I'm left to rely on the kind folks of this forum to help me however they can!
 

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