Electric Field: Find Electric Field from 2 Infinite Planes

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SUMMARY

The discussion focuses on calculating the electric field at specific points in the xy plane due to two infinite planes with uniform surface charge densities of 65 nC/m² and 45 nC/m². The first plane lies in the xz plane, while the second intersects the z-axis at a 30-degree angle. The electric field from the first plane is directed upward, while the second plane's contribution requires considering the angle between the electric fields, which is determined to be 150 degrees for the second point of interest. The relevant formula used for calculating the electric field is E = 2 * k * π * σ.

PREREQUISITES
  • Understanding of electric fields and surface charge density
  • Familiarity with trigonometric functions, particularly tangent
  • Knowledge of vector components and angles in physics
  • Proficiency in using the formula E = 2 * k * π * σ for electric fields
NEXT STEPS
  • Study the derivation and application of the formula E = 2 * k * π * σ in different geometries
  • Learn about the superposition principle for electric fields from multiple charge distributions
  • Explore the concept of electric field lines and their representation in space
  • Investigate the effects of angle and distance on electric field strength and direction
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by charged planes.

nns91
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Homework Statement



AN infinite plane in the xz plane carries a uniform surface charge density 65 nC/m^2. A second infinite plane carrying a uniform charge density 45 nC/m^2 intersect the xz plane at the z axis and makes an angle of 30 degree with the xz plane. Find the electric field in the xy plane at
(a) x=6m, y=2m
(b) x=6m, b=5m

Homework Equations



E=2*k*\pi*\sigma

The Attempt at a Solution



So the electric field due to the xz plane will be only in j direction (upward) so I just use the formula above to get the electric field.

Then how can I move on with the electric field due to the remaining plane ? I don't really know what do I use the position for
 
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Find E1 and E2 due to the two planes using relevant equation.
in (a) tanθ = y/x = 2/6 = 1/3. So θ < 30 degrees. Hence point lies between the planes.
In that situation what is angle between the electric fields?
Similarly see what happens in (b).
 
Will it be 150 degree ?
 
nns91 said:
Will it be 150 degree ?
Yes.
 
so do I use this 150 degree to calculate the component of the Electric field due to the 2nd plane ?

The electric field due to the first plane is just in y direction (upward), right ?
 
Yes.
 

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