Electric Field from Point Charges

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SUMMARY

The discussion focuses on calculating the electric field components at point P due to two point charges, q1 = -2.6 µC and q2 = 8.6 µC, separated by 9.7 cm. The x-component Ex(P) and y-component Ey(P) of the electric field were derived using the equation E = (kq)/r², with specific attention to significant figures. The user encountered errors in arithmetic and significant figures while calculating these components, leading to incorrect results. The discussion also touches on how to adjust charge Q1 to achieve a zero electric field at point P.

PREREQUISITES
  • Understanding of Coulomb's Law and electric field calculations
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of significant figures in scientific calculations
  • Experience with vector addition of forces or fields
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  • Review the application of Coulomb's Law in electric field calculations
  • Learn about vector addition in the context of electric fields
  • Study the significance of significant figures in physics calculations
  • Explore the effects of charge manipulation on electric fields
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Students studying electromagnetism, physics educators, and anyone involved in solving problems related to electric fields and point charges.

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Homework Statement


Two point charges (q1 = -2.6uC and q2 = 8.6uC) are fixed along the x-axis, separated by a distance d = 9.7cm. Point P is located at (x,y) = (d,d)

1. What is Ex(P), the x-component of the electric field produced by q1 and q2 at point P?
2. What is Ey(P), the value of the y-component of the electric field produced by q1 and q2 at point P?
3.A third charge is now positioned along the y-axis at distant d from and above q1 on (x,y) = (0,d). What is the Ex(P) of the field produced by all 3 charges at point P?
4. Suppose all are doubled, how will the electric field change?
5. How would you change Q1 in order to make the eletric field at point P equal to zero?


Homework Equations


E = (kq)/r^2
Exq1 = ((kq)/r^2)cos(45)
Exq2 = 0
Eyq1 = ((kq/r^2)sin(45)
Eyq2 = (kq)/r^2
C^2 = A^2 + B^2

Image for 1 and 2
h2_pointA.png


Image for 3, 4, and 5
h2_pointC.png


The Attempt at a Solution


1. First off, I drew the triangle of q1-q2-P and labelled all d values as 0.097m, used E=(kq)/r^2 to find the magnitude of E at point P a distance r = sqrt(2d^2) and then multiply that value by cos(45) to find that Exq1 is equal to -120608.8429 N/C by having q = 2.6e-6 C, k = 8.987551e9 and r = (which apparently is wrong)

2. Ey = Eyq1 + Eyq2, where Eyq1 = ((kq1)/r^2) * sin45 and Eyq2 = (kq2)/d^2. For Eyq1 I calculated -120451.7144 N/C and for Eyq2 I calculated 8214787.82 N/C. The sum of the two is 8094336.106 N/C which again, is apparently wrong.

I have not yet attempted 3,4 or 5 because I recognize after the first two I'm clearly doing something wrong in my steps.
 
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First off, you are using way too many significant figures. The data you are given only have 2 significant figures, so your answers should have no more than that.

Now, looking at part 1, your procedure seems correct, so you should double check your arithmetic. Make sure whatever you are using to calculate the cosine is expecting degrees and not radians.
 
I realize that the sig figs aren't accurate. I use smartphysics for my homework assignments and it is notorious for not accepting correct sig figs. My problem was that I did not actually do the arithmetic correctly.

Thank you
 
Even if your program or calculator gives you many digits, you should only report those that are significant. As for arithmetic mistakes, we all make them.
 
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