goWlfpack said:Homework Statement
Three point charges are located at the corners of an equilateral triangle as in the figure below. Find the magnitude and direction of the net electric force on the 1.00 µC charge.
(A = 1.00 µC, B = 6.50 µC, and C = -4.20 µC.)
magnitude N
direction ° counterclockwise from the +x-axis
Homework Equations
The Attempt at a Solution
I really have no idea where to even start.
goWlfpack said:I really don't know. I know that to find the electric field you use E=ke q1/r1^2 to find the E for the point. However i don't really know how to manipulate the equations to find the answers
An electric field is a physical quantity that describes the force experienced by a charged particle placed in its vicinity. It is created by electric charges and is represented by a vector quantity.
The electric field from two point charges can be calculated using the Coulomb's law. This law states that the electric field at a point is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The direction of the electric field from two point charges depends on the relative positions and charges of the two charges. The electric field points away from a positive charge and towards a negative charge.
Yes, it is possible for the electric field from two point charges to cancel each other out. This can occur if the magnitudes of the two charges are equal and they are placed at equal distances from the point of interest.
The electric field from two point charges is inversely proportional to the square of the distance between them. This means that as the distance between the two charges increases, the electric field decreases. Similarly, when the distance decreases, the electric field increases.