Electric Field: Homework Solutions

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SUMMARY

The discussion centers on calculating the electric field generated by two large non-conducting sheets with identical positive charge distributions, denoted by sigma (σ). The correct formula for the electric field above the sheets is σ/ε₀, where ε₀ represents the permittivity of free space. The principle of superposition is essential in this scenario, as the upward electric field from the top sheet (σ/2ε₀) does not cancel out with the downward field from the bottom sheet, leading to a net electric field of σ/ε₀ above the sheets.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with the principle of superposition in electrostatics
  • Knowledge of the permittivity of free space (ε₀)
  • Basic proficiency in vector addition of electric fields
NEXT STEPS
  • Study the derivation of electric fields from infinite plane sheets of charge
  • Learn about the principle of superposition in electrostatics
  • Explore the concept of electric field lines and their representation
  • Investigate the effects of negative charge distributions on electric fields
USEFUL FOR

Physics students, educators, and anyone studying electrostatics or preparing for exams in electromagnetism will benefit from this discussion.

auk411
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Homework Statement



see below.

Homework Equations


The Attempt at a Solution

 
Last edited:
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See the attachment for the visual, but ignore the negative charges. They aren't supposed to be there.

The image is of two large non-conducting sheets with identical distributions of positive charge. What is the value of the electric field above the sheets? sigma is the symbol for the identical distribution of positive charge.

I know the answer: [itex]\sigma[/itex]/epsilon[itex]\epsilon<sub>0</sub>[/itex]

I know that you need to add to use the principle of superposition.

However I still don't get the answer. The top sheet adds [itex]\sigma[/itex]/2epsilon[itex]\epsilon<sub>0</sub>[/itex] upwards. The downwards from the top sheet is canceled out by the upwards (electric field) from the bottom sheet. The bottom sheet has an electric field that also points in the negative y direction but with the same magnitude. So everything cancels out. So the electric field is zero.

This is wrong. However, I still do not see why and why the right answer is right.
 

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