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Electric field in a platinum wire

  • Thread starter sdevoe
  • Start date
21
0
1. Homework Statement

Consider a platinum wire (σ = 1.0e+7) with a cross-sectional area of 1 mm^2 (similar to your connecting wires) and carrying 0.3 amperes of current, which is about what you get in a circuit with a round bulb and two batteries in series. Calculate the strength of the very small electric field required to drive this current through the wire.

2. Homework Equations

σ=qnu
I=qnAuE
Therefore I=σAE
where phi is the conductivity A the cross sectional area and E the electric field

3. The Attempt at a Solution
This seemed easy but i got an answer of 3e-5 and that is incorrect?
 
21
0
Never mind i figured it out
 
How did you do it? I am where you were in the first post.
 
Hey I figured it out.
The only problem was dealing with units.
I just multiplied the 3e-5 by 1000 and got .03 as the right answer.
 

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