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Electric field in a platinum wire

  1. Mar 25, 2009 #1
    1. The problem statement, all variables and given/known data

    Consider a platinum wire (σ = 1.0e+7) with a cross-sectional area of 1 mm^2 (similar to your connecting wires) and carrying 0.3 amperes of current, which is about what you get in a circuit with a round bulb and two batteries in series. Calculate the strength of the very small electric field required to drive this current through the wire.

    2. Relevant equations

    σ=qnu
    I=qnAuE
    Therefore I=σAE
    where phi is the conductivity A the cross sectional area and E the electric field

    3. The attempt at a solution
    This seemed easy but i got an answer of 3e-5 and that is incorrect?
     
  2. jcsd
  3. Mar 25, 2009 #2
    Never mind i figured it out
     
  4. Nov 1, 2010 #3
    How did you do it? I am where you were in the first post.
     
  5. Nov 1, 2010 #4
    Hey I figured it out.
    The only problem was dealing with units.
    I just multiplied the 3e-5 by 1000 and got .03 as the right answer.
     
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