Electric field in a platinum wire

[sdevoe]

Homework Statement

Consider a platinum wire (σ = 1.0e+7) with a cross-sectional area of 1 mm^2 (similar to your connecting wires) and carrying 0.3 amperes of current, which is about what you get in a circuit with a round bulb and two batteries in series. Calculate the strength of the very small electric field required to drive this current through the wire.

Homework Equations

σ=qnu
I=qnAuE
Therefore I=σAE
where phi is the conductivity A the cross sectional area and E the electric field

The Attempt at a Solution

This seemed easy but i got an answer of 3e-5 and that is incorrect?

 

[sdevoe]

Never mind i figured it out

 

[tkrzeminski3]

How did you do it? I am where you were in the first post.

 

[tkrzeminski3]

Hey I figured it out.
The only problem was dealing with units.
I just multiplied the 3e-5 by 1000 and got .03 as the right answer.