Electric Field/ infinite charged sheet

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SUMMARY

The discussion revolves around the electric field generated by three infinite charged sheets with varying charge densities. The electric field due to an infinite sheet is defined by the formula E = σ/2ε, where σ represents charge density and ε is the permittivity constant. The confusion arises from the observation that the center sheet, with a charge density of σ = -2σ0, produces electric field vectors of double the magnitude compared to the other sheets, which have a charge density of σ = +1. This discrepancy is clarified by understanding that the electric field's magnitude is directly proportional to the charge density of each sheet.

PREREQUISITES
  • Understanding of electric fields and charge density
  • Familiarity with Gauss' Law and its applications
  • Knowledge of the permittivity constant (ε)
  • Basic vector analysis in physics
NEXT STEPS
  • Study the derivation of the electric field due to infinite sheets using Gauss' Law
  • Explore the implications of varying charge densities on electric field strength
  • Learn about the concept of superposition in electric fields
  • Investigate the effects of multiple charged sheets on electric field direction and magnitude
USEFUL FOR

Physics students, educators, and anyone interested in understanding electric fields generated by charged sheets and their implications in electrostatics.

Andy13
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Homework Statement


There are three charged sheets with various charge densities. The following link shows a diagram, and solutions (not mine; these are some professor's solutions but I don't understand them yet):

http://www.phy.syr.edu/courses/PHY212.08spring/HW/WHW-3.pdf

Draw vectors at each of the points A-D to show the direction and relative magnitude at the point due to a) sheet 1 b) sheet 2 c) sheet 3.

Homework Equations



E field due to infinite sheet = σ/2ε
(where ε = permittivity constant and σ = charge density)

Flux = ∫ EdA = E*A = |E||A|cos(θ)

Gauss' Law: Flux = q(enclosed)/εo

The Attempt at a Solution



I know which direction the vectors go, but I don't know what their magnitudes are. Surfing the internet gave me this (scroll to last page):

http://www.phy.syr.edu/courses/PHY212.08spring/HW/WHW-3.pdf

I know that the magnitudes of each vector of the electric field from each individual sheet from points A-D should be equal, because the electric field from a charged sheet doesn't depend on radius (for example, sheet 1's field could give vectors of magnitude |a| at every point).

However, I don't understand why sheet 2 (σ = -1), according to the above solutions, has vectors of twice the magnitude of sheets 1 and 3 (σ= +1). What am I missing?
 
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I agree with you.

His solution is consistent with the center sheet having a surface charge density of -2σ0 .

(I have taught this subject for more than 20 years.)
 
SammyS said:
I agree with you.

His solution is consistent with the center sheet having a surface charge density of -2σ0 .

(I have taught this subject for more than 20 years.)

Thanks SammyS-- I'm glad I wasn't misunderstanding something.
 

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