Electric Field of a Capacitor with asymmetric dielectric

[Mikey789]

Hey guys,
if an question regarding a capacitor.
As seen in the picture there is a capacitor with an asymmetric dielectric e1 and e2.

http://img129.imageshack.us/img129/5999/kondensatorti8.jpg

My question:
Who do I calculate the E-field of the capacitor?

thanks in advamce, help is appreciated!
Mike

 

[berkeman]

Thread moved to homework help.

You generally need to show your own work in order for us to provide tutorial assistance. This is a tricky problem, so I'll offer one initial hint -- would it change the problem at all if you put in a floating metal plate at the green/beige boundary on the left and one on the green/beige boundary on the right? Try picturing that, and think about how capacitors in series add. Please show your work...

 

[Mikey789]

Thread moved to homework help.

You generally need to show your own work in order for us to provide tutorial assistance. This is a tricky problem, so I'll offer one initial hint -- would it change the problem at all if you put in a floating metal plate at the green/beige boundary on the left and one on the green/beige boundary on the right? Try picturing that, and think about how capacitors in series add. Please show your work...

Ok,
I know that the problem is in the middle...

If I just take the the left and the right part I have two capacitors in series.. which isn't a problem at all... the D-Fields are equal througout the capacitor and the E-Fields "change" at the boundary.. no problem here...

Now I take the middle part...
Depending on where I put the Gaussian surface I get inconsistent results... (see image 2)
In order to make the inconsistancy disapear I place electrons(+ or -) on the vertical part of the boundry.

->that would leave me with three capacitors in parallel

Is that correct?

Thanks

 

[berkeman]

I would have split it in two. Why are you thinking of three?