(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A charge of 18 nC is uniformly distributed along a straight rod of length 4.7 m that is bent into a circular arc with a radius of 2.4 m. What is the magnitude of the electric field at the center of curvature of the arc?

2. Relevant equations

E=KQ/R^2

3. The attempt at a solution

dQ=[tex]\lambda[/tex]ds

[tex]\lambda[/tex]=Q/[tex]\pi[/tex]R

dQ=[tex]\lambda[/tex]Rd[tex]\Theta[/tex]

magnitude dE=kdQ/R^2=K[tex]\lambda[/tex]Rd[tex]\Theta[/tex]/R^2=KQd[tex]\Theta[/tex]/R^2

sin[tex]\Theta[/tex]magnitude dE=KQd[tex]\Theta[/tex]sin[tex]\Theta[/tex]/R^2

magnitude Ey=KQ[-cos[tex]\Theta[/tex]]from a to b/[tex]\pi[/tex]R^2

the limits of integration would be a=0 and b=4.7(2[tex]\Pi[/tex])/2[tex]\Pi[/tex]R

I got E=4.31e-1 n/c but it was wrong.

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# Homework Help: Electric field of a charged arc

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