Electric Field of a Dielectric Sphere

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Homework Help Overview

The discussion revolves around calculating the electric potential at the center of a uniformly charged dielectric sphere with radius R. Participants are exploring the electric field both inside and outside the sphere as part of this problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find the electric field in both regions of the sphere and consider integrating the electric field to determine the potential. There are questions about the expression for the electric field outside the sphere, with one participant expressing uncertainty about how to proceed.

Discussion Status

Some guidance has been offered regarding the use of Gauss's Law to find the electric field in the different regions. Multiple interpretations of the electric field expressions are being explored, particularly concerning the outside field.

Contextual Notes

One participant notes a specific answer for the potential, which may influence the discussion, but the context of how this answer is derived remains under exploration.

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Homework Statement


A uniform charge q is distributed along a sphere of radius R.
a) What is the Electric Potential in the center of the sphere?



Homework Equations


V(r1)-V(r0) = - [tex]\int \stackrel{\rightarrow}{E}[/tex] * [tex]\stackrel{\rightarrow}{dl}[/tex]


The Attempt at a Solution

 
Last edited:
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You will need to find the electric field both inside and outside the field and integrate the expression you posted from infinity to R using the field outside and then from R to zero using the field inside.
 
Thanks for answering, but actually I can't find the expression for the second part of the Electric field

The first is inside the sphere which leads to [tex]\frac{Kq}{R}[/tex] but the Electric field of the outside part of the sphere I don't know what to do

obs: the answer is : [tex]\frac{6kq}{R}[/tex]
 
Use Gauss's Law to find the field in the two regions.
 

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