Electric field of a non-conducting shell

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SUMMARY

The discussion focuses on calculating the electric field of a hollow spherical non-conducting shell with charge density p = C/r², defined within the inner radius a and outer radius b. The electric field is determined for three regions: inside the shell (r < a), within the shell (a < r < b), and outside the shell (r > b). The results confirm that the electric field is zero for r < a, E = C(r-a)/r²ε₀ for a < r < b, and E = C(b-a)/r²ε₀ for r > b. The calculations utilize Gauss's law and the appropriate volume integrals for charge density.

PREREQUISITES
  • Understanding of Gauss's law in electrostatics
  • Familiarity with spherical coordinates and volume integrals
  • Knowledge of electric field concepts and charge density
  • Basic calculus for integration and solving equations
NEXT STEPS
  • Study the application of Gauss's law in different geometries
  • Learn about electric fields generated by various charge distributions
  • Explore the concept of electric potential in relation to electric fields
  • Investigate the properties of non-conducting materials in electrostatics
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Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric fields in non-conducting materials.

motyapa
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Homework Statement



Not sure if I'm doing this problem correctly (no answer key for these practice problems). I just want to check with people that know this material well enough.

A hollow spherical non-conducting shell of inner radius a and outer radius b carries charge density p = C/r^2 in the region a =< r =< b. Find the electric field in the following regions

r < a
a < r < b
r > b

Homework Equations


[/B]
\varepsilon_0\int E \cdot dA = Qenc

The Attempt at a Solution


[/B]
for r < a

Qenc = 0 so E = 0

for a < r < b

Qenc = \int _a^r pdV

Volume of a sphere with radius r 4/3 \pi r^3

so then dV = 4\pi r^2 dr

which means Qenc = \int_a^r C/r^2 4\pi r^2 dr or \int_a^r4C \pi dr

Solving I get Qenc = 4\pi C (r-a)

Now that I have Qenc I can use

\varepsilon_0\int E \cdot dA = Qenc

using a gaussian surface of a sphere with radius r, I do

\varepsilon_0EA = 4\pi C (r-a)

A = 4\pi r^2 so that leaves me with

E = C(r-a)/r^2\varepsilon_0

for r > b

I used a similar process except I did

Qenc = \int _a^b pdV

making Qenc = 4\pi C (b-a)

so then E = C(b-a)/r^2\varepsilon_0while my answers make sense to me, I'd like to make sure I'm not making any mistakes because this question is harder than anything I've done so far!
 
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It is correct, nice work!
 

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