Electric Field of an Infinitely Long Insulating Cylinder

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Homework Help Overview

The problem involves determining the electric field of an infinitely long insulating cylinder with a volume charge density that varies with the radius. The inquiry is focused on applying Gauss's law to find the electric field at different radial distances from the cylinder's axis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Gauss's law and the need to consider the charge distribution correctly. There is a focus on integrating the charge density rather than using a simplified area calculation.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the correct approach to integrating the charge density. Some guidance has been offered regarding the need for integration to find the mass within a certain radius.

Contextual Notes

Participants are navigating the complexities of the problem, including the implications of the varying charge density and the assumptions necessary for applying Gauss's law effectively.

sicrayan
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Homework Statement


An infinitely long insulating cylinder of radius R has a volume charge density that varies with the radius as given by the following expression where ρ0, a, and b are positive constants and r is the distance from the axis of the cylinder.
symimage.cgi?expr=rho%3Drho_0%28a-r%2Fb%29.gif

Use Gauss's law to determine the magnitude of the electric field at the following radial distances. (Use the following as necessary: ε0, ρ0, a, b, r, and R.)
(a) r < R
(b) r > R

Homework Equations


gauss's law
 

Attachments

  • symimage.cgi?expr=rho%3Drho_0%28a-r%2Fb%29.gif
    symimage.cgi?expr=rho%3Drho_0%28a-r%2Fb%29.gif
    565 bytes · Views: 797
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hi sicrayan! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Hi
Thank you for your answer.
My unsuccessful solution:
lets take the length l,
for r<R,
WEyjR.png

why?
 
Last edited:
hi sicrayan! :smile:

no, you're taking the mass inside radius r as πr2 times ρ(r) …

it isn't, you need to integrate :wink:
 

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