Electric Field of Equilateral Triangle

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SUMMARY

The discussion focuses on calculating the electric field at the center of an equilateral triangle with a side length of 15.6 cm, where a charge of +2.0 μC is located at one vertex and -4 μC charges are at the other two vertices. The electric field (E) is determined using the formula E = kQ/r², where k is Coulomb's constant. The methodology for vector addition of the electric field components was confirmed as correct by other participants in the discussion.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with vector addition in physics
  • Knowledge of equilateral triangle geometry
  • Basic proficiency in using the formula E = kQ/r²
NEXT STEPS
  • Explore the concept of electric field superposition
  • Learn about vector components in two-dimensional physics problems
  • Study the effects of different charge configurations on electric fields
  • Investigate the applications of electric fields in real-world scenarios
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields in geometric configurations.

Brendan Webb
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Homework Statement


Consider an equilateral triangle of side 15.6cm. A charge of +2.0μC is placed at one vertex and charges -4μC each are placed at the two. Determine the electric field at the centre of the triangle.

Homework Equations


E=kQ/r^2

The Attempt at a Solution


I am hoping someone can check my methodology and possibly my answer too and let me know if it looks correct. I calculated the components of the vectors and added them and I believe I have it correct.
Part 1 of Question 4.jpg
Part 2 of Question 4.jpg


Thanks
 
Physics news on Phys.org
Your methodology and numbers are correct.
 
Thanks!
 

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