[SOLVED] Electric Field, solving for distance 1. The problem statement, all variables and given/known data A 18.8 nC charge is located at position ( x,y ) = (1.0cm, 2.0cm). At what (x, y) position(s) is the electric field a) -225,000i^ N/C (Where i^ is "i" with a hat on it... easier to explain this than look up the text code) b) (161,000i^ + 80,500j^) N/C c) (21,600i^ - 28,800j^) N/C 2. Relevant equations E = kQ/r^2 Aka, r = Sqrt(169.2 / E) 3. The attempt at a solution a) Plugged in E into r = Sqrt(169.2 / E). I then factored in the fact that the charge is not at the origin. Got a final answer of -1.74cm. This is correct. b) Tried the same thing here. There are two answers I need, one for the X position, one for the Y. I tried ignoring the Y, and just solving the X position using 161,000i^. Factored in the fact that the charge is not at the origin, got +4.24cm. This is incorrect. I see that my reasoning works in 1d, but once we involve the 2nd dimension, something is screwing me up. What am I not taking into account?