Electric Field Strength: Calculating for 0.75 g Plastic Bead

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Homework Help Overview

The discussion revolves around calculating the electric field strength required to suspend a charged plastic bead weighing 0.75 g, which has been charged with a specific number of excess electrons.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between electric field strength and the weight of the bead, with one suggesting that the electric field must equal the weight for suspension. Others discuss the force exerted by the electric field on a charge and the application of relevant equations.

Discussion Status

The discussion includes various interpretations of the problem, with participants attempting to connect the concepts of force, electric field, and charge. Some guidance has been offered regarding the equations involved, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants are navigating through the implications of the charge and weight of the bead, as well as the relationships defined by Coulomb's law and electric field equations. There may be assumptions regarding the setup that are being questioned.

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Electric field...please help!

Homework Statement


A 0.75 g plastic bead is charged by the addition of 8.28×10^10 excess electrons. What electric field (strength) will cause the bead to hang suspended in the air?


Homework Equations





The Attempt at a Solution


Doesn't E have to equal the weight? So would I just calculate the weight of the bead? That seems to easy though...
 
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The weight and the charge. Also, remember Force = E*q.
 
So...
(K*Q1*Q2) / R^2 = (KQ1) / R^2 * Q
And then I solve for Q?
But then I get Q2 = Q?? I am confused...
 
Let E be the unknown electric field. Then what is the force it exerts on a charge q? I've already told you...
 
E = Force / Q
Force = K*Q1*Q2 / r^2
 

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