Statistics of charged beads in electric field

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Homework Help Overview

The problem involves a string of charged beads connected by rigid rods in an electric field, focusing on the average length of the string when only the last bead is charged. The context is rooted in statistical mechanics and electric potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the effects of the charged bead in the electric field, considering the alignment of rods and the resulting energy states. Questions arise about how to express the energy of the system and the relationship between the orientations of the rods and the position of the charged bead.

Discussion Status

Some participants have provided insights into defining variables for the orientations of the rods and how to calculate the potential energy based on these orientations. There is an ongoing exploration of the partition function and its implications for determining probabilities related to the alignment of the rods.

Contextual Notes

Participants are navigating the complexities of the problem, including the influence of the electric field on the entire system and the assumptions regarding the initial conditions of the beads. There is a focus on ensuring correct signs in energy expressions and clarifying the summation limits for the length calculation.

Beer-monster
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Homework Statement



Consider a string of N beads connected by N-1 rigid rods of length l. The system is considered as one-dimensional with rods only being aligned either up or down. The string is immersed in a fluid at temperature T and first bead is fixed at the origin y=0. A constant electric field is applied in the positive y direction.

What is the average length of the string if only the last bead holds a charge q.


Homework Equations



\sum\frac{e^{-\beta E}}{Z}


The Attempt at a Solution



I'm a little unsure about how to consider the effects of the charged bead in the field.

My thoughts in general were to consider the rods in two states, either aligned with or against the field. If aligned with the field the energy is negative -eEl. If aligned with the field the energy is positive +eEl. By considering these states I hope to determine the probability of a rod being aligned with/against field and from that determine the expectation value of the length.

One one hand if only the end bead is charged only that bead will show a preferential alignment and the rest will be random.

On the other hand; if the Nth bead feels a force due to the applied field it will also apply a force to the N-1th bead, which will apply the force to the N-2th bead etc. In that way the work will be applied to all of the rods so the energy shift will apply to all beads.

Which is right? Or am I completely off-base?
 
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For the partition function, you need an expression for the energy of the system for each possible state of the system. A state of the system is a specification of the orientations of the individual rods. The energy of the system is equal to the electrical potential energy of the charged bead and that’s determined by the charged bead’s y coordinate, yN.

If you knew the orientations of all the rods, how could you calculate yN? It might be helpful to introduce a variable for each rod to denote it’s orientation, say sk for the kth rod. Let sk = 1 or -1 for the rod being parallel or antiparallel to the field, respectively. Can you express yN in terms of the sk variables and the length of each rod?

How would you express the electrical potential energy of the system in terms of yN?
 
Last edited:
If we define Sk as +/-1 depending on if the rods are aligned with the field the length of the string would be:

y_{N}=\sum_{N} S_{k}l where l is the length of a rod.

In the absence of an initial coordinate for the Nth bead I would express the potential energy of due to the field as \epsilon = q_{N}Ey_{N}

Thus the partition function per rod would be

Z = \sum^{+1}_{S_{k}=-1} e^{\beta q_{N}E\sum_{N} S_{k}l}

Using this I can determine the probability and thus the average number of a rod being aligned with or against the field and sum to make the average length.
 
Beer-monster said:
If we define Sk as +/-1 depending on if the rods are aligned with the field the length of the string would be:

y_{N}=\sum_{N} S_{k}l where l is the length of a rod.
Yes. The sum is over k from 1 to N-1?
In the absence of an initial coordinate for the Nth bead I would express the potential energy of due to the field as \epsilon = q_{N}Ey_{N}

The potential energy of a (positive) charge decreases as the charge moves in the direction of the field. So, the sign is not correct for the energy.
Thus the partition function per rod would be

Z = \sum^{+1}_{S_{k}=-1} e^{\beta q_{N}E\sum_{N} S_{k}l}

Here, the sign of the argument of the exponential is correct!
Using this I can determine the probability and thus the average number of a rod being aligned with or against the field and sum to make the average length.

Yes.
 
Last edited:

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