Electric field vector due to very long thread

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Homework Help Overview

The problem involves calculating the electric field vector due to two parallel, uniformly charged threads with a specified linear charge density and distance between them. The focus is on understanding the contributions of each thread to the total electric field at a point equidistant from both threads.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply Gauss's law to determine the electric field due to each thread and questions whether the total field can be found by simply adding the magnitudes. Participants discuss the directionality of the electric fields and the implications of vector addition.

Discussion Status

Participants are exploring the relationship between the electric fields from both threads, with some guidance provided on considering the vector nature of electric fields. There is an ongoing examination of how the fields interact at the specified point, with no consensus reached yet.

Contextual Notes

Participants are navigating the complexities of vector addition in the context of electric fields, particularly in relation to the geometry of the problem and the positioning of the threads.

Aleksandre
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Homework Statement


Two parallel very long threads are uniformly charged with linear charge density of 10-8 C/cm . Distance between them is 15 cm. Find electric field vector at a distance of 15 cm from both threads.

Homework Equations



E*dA=Qenclosed/permittivity of free space

The Attempt at a Solution



So I assumed that the electric fields created by each thread would be equal as they have same characteristics. So to solve the problem I just had to find electric field created by a long thread. To solve it, I used Gaussian law (enclosed the thread with a cylinder of radius R=15cm and length L), the equation above which led me to:

E*2pi*R*L=Qenclosed/epsilon where Qenclosed = charged density lambda * L

E*2pi*R*L = lambda * L / epsilon
Uknown Ls cancel out, R is a intial distance 0.15 m so I can solve for E. The final electric field found, will be same for second thread as well. Is this solution correct?
 
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You're OK so far, for the magnitude of the field due to each thread separately.

How do you propose to find the total field due to the two threads together?
 
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jtbell said:
You're OK so far, for the magnitude of the field due to each thread separately.

How do you propose to find the total field due to the two threads together?

Just add them up? so 2*E?
 
Aleksandre said:
Just add them up? so 2*E?
Are they in the same direction? Remember ##\vec E## is a vector quantity.
 
They have opposite direction and same magnitude so would it be zero?
 
Aleksandre said:
They have opposite direction
Can you draw a diagram that shows how that can be true at a point that is 15cm from each thread, while the threads themselves are separated by 15cm?
 
No. Now I'm really stuck can I get a hint?
 
In this diagram, the two threads are perpendicular to the screen or page, so they appear as points. There are two points on the screen that are 15cm from both threads. Where are they?

threads.gif
 

Attachments

  • threads.gif
    threads.gif
    4.1 KB · Views: 625
Ok I got it thanks. I was looking to threads from left view and could not see that.
 

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