# Electric Field with a Solid Spherical Conductor

• Yosty22
In summary, the electric field in the cavity of a spherical conductor with a spherical cavity that is not centered on the center of the conductor is zero. This is because the charges in the cavity are evenly distributed on the outer surface of the conductor, resulting in a cancellation of the electric field inside the cavity. Drawing a Gaussian surface around the cavity would show that there is no net charge enclosed, further supporting the fact that the electric field in the cavity is zero. This may seem counterintuitive due to the lack of symmetry, but it is supported by the continuity relation and can be seen through mathematical calculations.

## Homework Statement

A spherical conductor has a spherical cavity in its interior. The cavity is not centered on the center of the conductor. If a positive charge is placed on the conductor, the electric field in the cavity

A. points generally toward the outer surface of the conductor.
B. points generally away from the outer surface of the conductor.
C. is zero.

NA

## The Attempt at a Solution

I'm thinking it should be C. A conductor has to have a net charge of 0 inside, so if you place a positive charge inside of the cavity, then the negative charges will be outside of the cavity. Therefore, the electric field could flow from the positive to the negative and I think the net electric field in the cavity would be zero.

Any confirmation or denial would be great.

Yosty22 said:
If a positive charge is placed on the conductor, the electric field in the cavity...

I'm thinking it should be C. A conductor has to have a net charge of 0 inside, so if you place a positive charge inside of the cavity...
... according to the problem statement, where is the charge?

Have you heard of Gausses Law?

Simon Bridge said:
... according to the problem statement, where is the charge?

I attached the picture that goes with the question. I was thinking that if you put a test charge in the center of the gap, then the Electric Field flows from the positive to the negative charges (the negative charges would be attracted to the positive charge in the gap and arrange themselves around the gap). Therefore, the electric field in the gap itself should be zero, correct?

#### Attachments

• Spherical Conductor.jpg
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I see - the "positive test charge" in the definition of the electric force has to be so small that it does not significantly displace the charges whose field you are testing. i.e. the test charge cannot attract negative charges to it.

There is actually an easier way to think about it - if you make a closed surface anywhere, then the electric field lines through that surface depend on the total charge enclosed by the surface. If there is no charge inside the surface, then there is no electric field.

Even easier - what is the electric field inside a charged conductor?

1 person
Ok, so if I were to create a Gaussian surface just around the cavity - not the whole system, there is no charge in the cavity, so there is no electric field inside the cavity, correct?

There you go - wasn't that simple!

When the conductor was charged, all the positive charge got evenly distributed about the outside skin.
The electric field everywhere inside is zero - does not matter what cavities there are.

Now I am very confused. My professor talked about this question in lecture today. He said that the answer should be B - points generally away from the outer surface of the conductor. I understand that the electric field lines from the positive charges should be pointed outwards, but why would that matter in the cavity? I thought the cavity should have no electric field.

He said that since there is not symmetry you cannot just draw a Gaussian surface around the cavity because the center of cavity is not the center of the conductor.

Why should this matter? Why can't you arbitrarily draw the Gaussian surface over the cavity, which would show that there is no net charge inside the cavity, therefore no electric field?

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Yosty22 said:
Now I am very confused. My professor talked about this question in lecture today. He said that the answer should be B - points generally away from the outer surface of the conductor. I understand that the electric field lines from the positive charges should be pointed outwards, but why would that matter in the cavity? I thought the cavity should have no electric field.

He said that since there is not symmetry you cannot just draw a Gaussian surface around the cavity because the center of cavity is not the center of the conductor.

Why should this matter? Why can't you arbitrarily draw the Gaussian surface over the cavity, which would show that there is no net charge inside the cavity, therefore no electric field?
Well ... if you charge two plates, there is an electric field between them even though there is no charge between them.

Darn - I'm afraid I've mislead you here.
Technically gausses law says that the net flux through a surface depends on the charges enclosed.
If all the charges are outside, then the same amount of flux enters as leaves so the net flux through the surface is zero. :(

Maybe I'm slipping ... I'd have thought that the charge would be uniformly distributed about the outer surface of the conductor. This should mean that the field will cancel for any position inside the sphere.

http://farside.ph.utexas.edu/teaching/em/lectures/node58.html
Even though the cavity is not centered in the sphere, you can still draw a gaussian surface centered on the sphere that completely encloses the cavity. There are no charges enclosed, therefore the the field through the surface is zero. This leaves the possibility of an uneven charge distribution outside the cavity - which is ruled out by the continuity relation.

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