Electric fields between point charges

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The discussion centers on the convention of referencing angles in relation to the positive x-axis rather than the y-axis when analyzing electric fields between point charges. Participants emphasize the need for clarity in terminology, suggesting that the phrase "angle from the line AP" is more accurate than "to the line AP." This focus on precision in language highlights the importance of standard conventions in physics. The repeated mention of these points underscores a shared understanding of the conventions used in vector analysis. Overall, the conversation reflects a commitment to clear communication in scientific discussions.
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Homework Statement
Question 2c: I've attempted the question, I've got the magnitude right but I got the angle wrong. I don't understand why the value of the components are swapped around.
Relevant Equations
Electric fields
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I’m guessing it’s just convention to reference the angle from the positive x-axis instead of the y-axis.

To nitpick your solution should say “angle from the line AP” not “to the line AP”
 
PhDeezNutz said:
I’m guessing it’s just convention to reference the angle from the positive x-axis instead of the y-axis.

To nitpick your solution should say “angle from the line AP” not “to the line AP”
PhDeezNutz said:
I’m guessing it’s just convention to reference the angle from the positive x-axis instead of the y-axis.

To nitpick your solution should say “angle from the line AP” not “to the line AP”
 

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PhDeezNutz said:
I’m guessing it’s just convention to reference the angle from the positive x-axis instead of the y-axis.

To nitpick your solution should say “angle from the line AP” not “to the line AP”
PhDeezNutz said:
I’m guessing it’s just convention to reference the angle from the positive x-axis instead of the y-axis.

To nitpick your solution should say “angle from the line AP” not “to the line AP”
 
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My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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