Electric fields of charged plates

Click For Summary
SUMMARY

The discussion centers on the calculation of the electric field between charged plates, specifically using the equation E = σ/2ε₀, where σ represents charge density and ε₀ is the permittivity of free space. Participants debated the relevance of distance in the context of large plates, concluding that distance becomes negligible when the point of interest is significantly less than the plate dimensions. A charge density of 300 C/m² was identified as excessively high, leading to an electric field calculation of E = 1.694 x 10¹³ N/C, which raised concerns about potential errors in the answer key provided by the professor.

PREREQUISITES
  • Understanding of electric fields and charge density
  • Familiarity with the equation E = σ/2ε₀
  • Knowledge of the concept of large charged plates in electrostatics
  • Basic proficiency in unit conversion and dimensional analysis
NEXT STEPS
  • Research the implications of charge density on electric field strength
  • Study the concept of infinite plane approximation in electrostatics
  • Learn about the significance of units in physics calculations
  • Explore common errors in electrostatics problem-solving and how to avoid them
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in solving electrostatic problems, particularly those related to electric fields and charged plates.

swinfen
Messages
7
Reaction score
0
Homework Statement
Find the magnitude of the electric field of a large plate with surface charge density of 300Cm2 at a point 2.00 m away from the surface?
Relevant Equations
E = σ/2e0
I thought it might be the case that the "2m away" wasn't applicable as the electric field doesn't change if the point away is less than the length of the plate, so I thought I should use the equation listed. All examples I can find talk about two charged plates, or the effect on cylinders through or around a charged plate.
 
Physics news on Phys.org
Hello @swinfen,
:welcome:##\qquad## !​
You have a relevant equation.
The cylinders are involved in the derivation of the equation.
What stops you from applying it ?

##\ ##
 
Thanks for your response BvU. Firstly, am I correct that the '2m away' is not relevant? If this is then the only equation to use, then I was marked wrong by the professor (they do not provide any feedback on wrong answers). The answer I gave was:

E = σ/2e0
=> E = 300/2*(8.854*10^-12)
=> E = 1.694*10^13
 
Perhaps you were punished for omitting the units ?
I can't think of anything else.
The distance should be << plate dimensions, but that is what the problem statement says.

##\ ##
 
Let me speculate...
The charge density of 300 C/m2 is too large and so is the electric field. As for the distance, it is irrelevant because the plate is large. Many times "large" means infinitely big.
 
Thanks for the feedback. Yes I realized that I missed the units on this one (only this one!) but even my one of the professors (who I finally managed to get in touch with and had tried to solve the problem) couldn't get the same answer as the answer key. So I think we must be right and the answer key must be wrong!
Now just need to understand the other problem I posted, if any of you would like to help with that one? :)
 
I can't see the other problem.
 

Similar threads

Replies
7
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
11
Views
3K
Replies
4
Views
3K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
1K
Replies
6
Views
2K