Electric Fields (Uniformly Charged Plates)

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SUMMARY

The discussion focuses on calculating the electric field produced by two large, thin metal plates with surface charge densities of ±7.76 × 10-22 C/m2. Using Gauss' Law, the electric field is derived for three regions: outside the plates (left and right) and between them. The pillbox method is emphasized for its necessity in enclosing charge, clarifying why both surfaces of the Gaussian surface must be considered in the calculations.

PREREQUISITES
  • Understanding of Gauss' Law
  • Familiarity with electric fields and charge distributions
  • Knowledge of the pillbox method in electrostatics
  • Basic concepts of surface charge density
NEXT STEPS
  • Study the application of Gauss' Law in various geometries
  • Learn about electric field calculations for different charge configurations
  • Explore the implications of surface charge density on electric fields
  • Investigate the concept of electric field lines and their representation
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in electrostatics and electric field calculations, particularly in the context of charged plates.

Ian Baughman
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Homework Statement



In the figure two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have excess surface charge densities of opposite signs and magnitude 7.76 × 10-22 C/m2. What is the magnitude of the electric field at points (a) to the left of the plates, (b) to the right of them, and (c) between them?
upload_2016-6-5_17-11-35-png.101718.png


Homework Equations

[/B]

Gauss' Law

The Attempt at a Solution


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So I understand how to solve this problem and I am getting the correct solution but I was hoping for some clarification When using the pillbox method for gauss' law you consider two areas, the top and bottom part of the cylinder that is penetrating the plane. In parts a and b we still consider both areas but why wouldn't we just consider the area to the left or area to the right? Hopefully this makes sense!
 
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Sorry about that! Here it is.
upload_2016-6-5_17-11-35.png
 
Ian Baughman said:
So I understand how to solve this problem and I am getting the correct solution but I was hoping for some clarification When using the pillbox method for gauss' law you consider two areas, the top and bottom part of the cylinder that is penetrating the plane. In parts a and b we still consider both areas but why wouldn't we just consider the area to the left or area to the right? Hopefully this makes sense!
You need a volume that encloses the charge. If you placed one face so that it is coincident with the charge, geometrically the charge would not be enclosed by the volume.
 

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