Electric Fields (Uniformly Charged Plates)

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Homework Help Overview

The discussion revolves around the electric field generated by two large, thin metal plates that have opposite surface charge densities. The problem specifically asks for the electric field's magnitude in three distinct regions: outside the plates and between them.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify the application of Gauss' Law using the pillbox method, questioning why both areas of the cylinder are considered when evaluating the electric field outside the plates.

Discussion Status

Some participants have engaged with the original poster's question, providing insights into the necessity of enclosing charge when applying Gauss' Law. The discussion is exploring the reasoning behind the method rather than reaching a consensus.

Contextual Notes

There is a mention of an image that is not visible, which may affect the clarity of the problem setup. The original poster's understanding of the solution process is noted, but specific details about the solution are not provided.

Ian Baughman
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Homework Statement



In the figure two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have excess surface charge densities of opposite signs and magnitude 7.76 × 10-22 C/m2. What is the magnitude of the electric field at points (a) to the left of the plates, (b) to the right of them, and (c) between them?
upload_2016-6-5_17-11-35-png.101718.png


Homework Equations

[/B]

Gauss' Law

The Attempt at a Solution


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So I understand how to solve this problem and I am getting the correct solution but I was hoping for some clarification When using the pillbox method for gauss' law you consider two areas, the top and bottom part of the cylinder that is penetrating the plane. In parts a and b we still consider both areas but why wouldn't we just consider the area to the left or area to the right? Hopefully this makes sense!
 
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Your image isn't visible; it may be behind a required login. Can you UPLOAD it instead?
 
Sorry about that! Here it is.
upload_2016-6-5_17-11-35.png
 
Ian Baughman said:
So I understand how to solve this problem and I am getting the correct solution but I was hoping for some clarification When using the pillbox method for gauss' law you consider two areas, the top and bottom part of the cylinder that is penetrating the plane. In parts a and b we still consider both areas but why wouldn't we just consider the area to the left or area to the right? Hopefully this makes sense!
You need a volume that encloses the charge. If you placed one face so that it is coincident with the charge, geometrically the charge would not be enclosed by the volume.
 

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