Electric Force and Superposition...Help

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SUMMARY

The discussion focuses on calculating the electric force on a charge Q due to two equal positive charges, each with a value of q = 2.0 × 10−6 C. The participants clarify the importance of correctly assigning signs to the X and Y components of the force vectors. The magnitude of the force is determined to be 0.29 N, with the X component being 0.23 N and the Y component needing careful consideration for sign assignment. The correct approach involves sketching the force vectors to visualize the direction and signs of the components.

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  • Familiarity with trigonometric functions (sine and cosine) in relation to angles
  • Ability to sketch and interpret force diagrams
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Amaliahch
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Homework Statement


Two equal positive charges, both q = 2.0 × 10−6 C, interact with a third charge, Q = 4.0 × 10−6 C, as shown in the figure above. What is the magnitude of the electric force on Q? (kC = 8.99 × 109 N•m2/C2)
Screen Shot 2016-05-15 at 5.22.23 PM.png

Homework Equations


I'm confused about assigning signs when I get to the part of finding the X and Y components of each vector towards Q
I don't know if the values for the components I found are correctly signed... I believe are all positive

The Attempt at a Solution


I find that the magnitude of both vectors since they are the same is O.29N
The X component of one vector is 0.23N and the Y component is 0.17N I think.
 
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Amaliahch said:
I'm confused about assigning signs when I get to the part of finding the X and Y components of each vector towards Q
I don't know if the values for the components I found are correctly signed... I believe are all positive
It can help if you sketch in the force vectors on your diagram. Both of the 'q' charges will produce a force vector on the 'Q' charge. If you examine the vectors that you sketch then you should be able to tell from them the appropriate signs of their components.
 
I did but according to my sketch all four would be positive. I'm doing something wrong I'm not sure what it is because one of them is supposed to be negative, one of the y components
 
Can you post your diagram with the force vectors?
 
this is what i drew
IMG_0201.JPG
 
Okay. So looking at your two force vectors I see one pointing into quadrant 1 and the other into quadrant 4. You should be able to assign the signs of the vector components just by looking at the diagram. Take a close look at the y-components...
 
So it would be like this?
Q2 going to Q both components would be positive
Q1 going to Q the X component would be positive (cosine is positive in the 4th quadrant) and Y component would be negative( sine is negative in the 4th quadrant)
 
Amaliahch said:
So it would be like this?
Q2 going to Q both components would be positive
Q1 going to Q the X component would be positive (cosine is positive in the 4th quadrant) and Y component would be negative( sine is negative in the 4th quadrant)
Yup.
 
Thank you!
 

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