Electric Force problem involving HCl and Br- on coordinate axis

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SUMMARY

The discussion centers on the electric forces acting on a bromide ion (Br-) in relation to a hydrogen chloride (HCl) molecule. The HCl molecule has a partial positive charge on the hydrogen atom and a partial negative charge on the chlorine atom. The forces acting on the bromide ion are influenced by the attractive force from the hydrogen and the repulsive force from the chlorine, resulting in a net force at a positive angle above the horizontal. The conclusion emphasizes the need to analyze the forces vectorially to determine the resultant direction accurately.

PREREQUISITES
  • Understanding of electric charge interactions (attractive and repulsive forces)
  • Familiarity with vector addition of forces
  • Knowledge of molecular structure and polarity, specifically in HCl
  • Basic principles of electrostatics and Coulomb's law
NEXT STEPS
  • Study vector addition in physics to analyze forces accurately
  • Learn about electrostatic forces using Coulomb's law
  • Explore molecular polarity and its effects on intermolecular forces
  • Investigate the concept of net force and equilibrium in charged systems
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Students studying chemistry or physics, particularly those focusing on electrostatics, molecular interactions, and force analysis in charged systems.

bbuilder
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Homework Statement



A hydrogen chloride molecule (HCl) has a partial positive charge on the hydrogen atom and a partial negative charge on the chlorine atom. The HCl molecule is placed at

A.
There will be force on the bromide ion in the +x direction.

B.
There will be force on the bromide ion in the -x​ direction.

C.
There will be force on the bromide ion in the +y​
There will be no force on the bromide ion. The attractive force from the positively charged hydrogen will be canceled out by the repulsive force of the negatively charged chlorine.




Homework Equations


p=qd


The Attempt at a Solution


I might be overthinking this problem. I was thinking that the bromide ion be in the positive x-direction to attract it to the partial positive negative ion. I'm confused about how the y-direction might come into play in this problem. I was also thinking that these charges might cancel out because they are directly opposite of each other on the x-axis.
 
Last edited:
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Hi bbuilder, welcome to PF.

Make a drawing showing the position of the atoms, and draw arrows showing the magnitude and direction of the forces.


ehild
 
The negatively charged chloride is on the -x-axis. The positively charged hydrogen is on the chloride ion has a force on the bromide ion at a positive angle above the horizontal. The positively
 
Last edited:
See the picture. As the HCl molecule is neutral, the positive charge on the hydrogen is equal in magnitude to that of the negative charge on the chlorine. As they are at equal distances from the bromine atom, both the hydrogen and the chlorine atom exert equal forces on the bromine, but the force of the hydrogen is attractive, that of the chlorine is repulsive. See the picture.

What is the direction of the resultant force on the bromine?

Read the problem carefully. All questions refer to the force applied on the bromine atom.

ehild.
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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