Electric Forces: Calculating Charge on Two Spheres

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SUMMARY

The discussion focuses on calculating the electric charge on two small metallic spheres suspended as pendulums, each with a mass of 0.14 g and positioned at an angle of 7° with the vertical. Using Coulomb’s constant (8.98755 × 109 N·m2/C2) and the acceleration due to gravity (9.81 m/s2), the charge was calculated to be approximately 1.44639 × 10-7 C. Participants noted the importance of ensuring unit consistency when converting the final answer to nanocoulombs (nC), which resulted in a value of 144.641 nC. The calculation method was confirmed as correct, but attention was drawn to the need to square the distance between the charges for accuracy.

PREREQUISITES
  • Understanding of Coulomb's Law and electric forces
  • Basic knowledge of trigonometry, particularly sine and cosine functions
  • Familiarity with unit conversions, especially between grams, centimeters, and Coulombs
  • Ability to solve equations involving tension and equilibrium in pendulum systems
NEXT STEPS
  • Study Coulomb's Law applications in electrostatics
  • Learn about the principles of pendulum motion and equilibrium
  • Explore unit conversion techniques for physics calculations
  • Investigate common errors in electric charge calculations and how to avoid them
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Students in physics, particularly those studying electrostatics and mechanics, as well as educators looking for practical examples of electric force calculations.

Kris1120
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Homework Statement



Two small metallic spheres, each of mass
0.14 g are suspended as pendulums by light
strings from a common point as shown. The
spheres are given the same electric charge, and
it is found that the two come to equilibrium
when each string is at an angle of 7◦ with the
vertical.
The value of Coulomb’s constant is
8.98755 × 109 N · m2/C2 and the acceleration
of gravity is 9.81 m/s2 .
If each string is 13.7 cm long, find the mag-
nitude of the charge on each sphere.
Answer in units of nC.


Homework Equations




y=Tcos(theta)=mg
x=Tsin(theta)=Fe

The Attempt at a Solution



Tcos(7)=(.14g)(9.81)
T=1.38371

1.38371sin(7)=.168632

q=sqrt((.1683632)(2*(.137sin7)^2))/8.98755x10^9
q=1.44639e-7
 
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Kris1120 said:

Homework Statement



Two small metallic spheres, each of mass
0.14 g are suspended as pendulums by light
strings from a common point as shown. The
spheres are given the same electric charge, and
it is found that the two come to equilibrium
when each string is at an angle of 7◦ with the
vertical.
The value of Coulomb’s constant is
8.98755 × 109 N · m2/C2 and the acceleration
of gravity is 9.81 m/s2 .
If each string is 13.7 cm long, find the mag-
nitude of the charge on each sphere.
Answer in units of nC.

Homework Equations


y=Tcos(theta)=mg
x=Tsin(theta)=Fe

The Attempt at a Solution


Tcos(7)=(.14g)(9.81)
T=1.38371
1.38371sin(7)=.168632

q=sqrt((.1683632)(2*(.137sin7)^2))/8.98755x10^9
q=1.44639e-7


Your method looks fine.

I haven't checked the math.
Have you been careful to make sure that the units of grams and cm's is properly matched to the units of g and Coulomb's constant?

Your answer needs to be in nC.
 
I changed it no nC and that is 1.44641e2 nC. It's still not right. :(
 
sorry i meant *to
 
Kris1120 said:
q=sqrt((.1683632)([2*(.137sin7)]^2))/8.98755x10^9
q=1.44639e-7

You need to square the total distance between the charges.
 

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