1. The problem statement, all variables and given/known data Two particles, one with charge -7.13 × 10-6 C and one with charge 1.87 × 10-6 C, are 0.0284 meters apart. What is the magnitude of the force that one particle exerts on the other? Two new particles, which have identical positive charge q3, are placed the same 0.0284 meters apart, and the force between them is measured to be the same as that between the original particles. What is q3? 2. Relevant equations Fe=Kq1*q2 /r^2 3. The attempt at a solution So for the first part. I got the answer right for the force which was 148.7 N. However for the second part, I tried doing Fe= kq3^2/r^2 and solved for q3. However I keep getting 3.6 x 10 ^-6 columbs and thats wrong according the my physics hw website. Any help where im going wrong?THanks!