- #1

GodPlaysDice

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## Homework Statement

The ammonia molecule (NH3) has a dipole moment of 5.0×10−30C⋅m. Ammonia molecules in the gas phase are placed in a uniform electric field E⃗ with magnitude 1.0×106N/C.

What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to E⃗ from parallel to perpendicular?

## Homework Equations

V = U/q

ΔU = -integral([itex]qE dl[/itex])

ΔV = -integral([itex]E dl[/itex])

E(r) = -∇V(r)

I have no idea what the upside down delta is...

## The Attempt at a Solution

I don't even know where to start.