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yeah cross product.Ok then I think its solved...Thanks a lot
Electric dipole in Uniform Electric Field (3D)
- Thread starter Arman777
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SUMMARY
An electric dipole with a magnitude of 0.2 Cm is placed in a uniform electric field of E = 100i + 70j + 40k N/C. The dipole is rotated from the x-axis to the z-axis and finally to the y-axis. The total work done by the external agent during this process is -6 J, which is equal to the change in potential energy (ΔU). The torque exerted by the electric field is calculated using τ = p x E, and the dipole is in static equilibrium when aligned with the y-axis, requiring an equal and opposite torque from the hand to maintain that position.
PREREQUISITES- Understanding of electric dipoles and their properties
- Familiarity with torque calculations in physics
- Knowledge of potential energy in electric fields
- Ability to perform vector cross products
- Study the concept of electric dipole moments in detail
- Learn about torque and equilibrium in rotational dynamics
- Explore the relationship between work and potential energy in conservative fields
- Practice vector cross product calculations with various examples
Students studying electromagnetism, physics educators, and anyone interested in understanding the dynamics of electric dipoles in electric fields.