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**1. Homework Statement**

Which point in the electric field in the diagram is at the lowest potential?

Figure: http://i131.photobucket.com/albums/p289/SoaringCrane/Tip24_fig3.gif

a.Point 1

b.Point 2

c.Point 3

c.Point 3

d.Point 4

e.Point 5

**2. Homework Equations**

See below.

**3. The Attempt at a Solution**

Equipotential lines are perpendicular to electric field lines, so dots in the same column have the same potential. Electric field lines go from high voltage to low voltage, so dots at the near right have the lowest potential? Rightmost is Point 3?

**1. Homework Statement**

Charges Q and q (Q is not equal to q), separated by a distance d, produce a potential V_p at point P.

Figure: http://i131.photobucket.com/albums/p289/SoaringCrane/Tip24_fig1.gif

This means that

a.no force is acting on a test charge placed at point P.

b.Q and q must have the same sign.

**c.the electric field must be zero at point P.**

d.the net work in bringing Q to a distance d from q is zero.

e.the net work needed to bring a charge from infinity to point P is zero.

**2. Homework Equations**

See below.

**3. The Attempt at a Solution**

Following the fact that V/m = N/C, the electric field will also be 0???

**1. Homework Statement**

Charges +Q and -Q are arranged at the corners of a square as shown.

Figure: http://i131.photobucket.com/albums/p289/SoaringCrane/Tip24_fig2.gif

When the electric field and the electric potential V are determined at P, the center of the square, we find that

a. E no equal 0; V>0

**b. E = 0; V = 0**

c. E = 0; V>0

d. E no equal 0; V<0

**2. Homework Equations**

See below.

**3. The Attempt at a Solution**

Well, if the vectors are drawn from the center, they cancel out so E = 0. If E=0, then wouldn’t the potential also be 0?

Thanks.

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