(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Which point in the electric field in the diagram is at the lowest potential?

Figure: http://i131.photobucket.com/albums/p289/SoaringCrane/Tip24_fig3.gif

a.Point 1

b.Point 2

c.Point 3

d.Point 4

e.Point 5

2. Relevant equations

See below.

3. The attempt at a solution

Equipotential lines are perpendicular to electric field lines, so dots in the same column have the same potential. Electric field lines go from high voltage to low voltage, so dots at the near right have the lowest potential? Rightmost is Point 3?

1. The problem statement, all variables and given/known data

Charges Q and q (Q is not equal to q), separated by a distance d, produce a potential V_p at point P.

Figure: http://i131.photobucket.com/albums/p289/SoaringCrane/Tip24_fig1.gif

This means that

a.no force is acting on a test charge placed at point P.

b.Q and q must have the same sign.

c.the electric field must be zero at point P.

d.the net work in bringing Q to a distance d from q is zero.

e.the net work needed to bring a charge from infinity to point P is zero.

2. Relevant equations

See below.

3. The attempt at a solution

Following the fact that V/m = N/C, the electric field will also be 0???

1. The problem statement, all variables and given/known data

Charges +Q and -Q are arranged at the corners of a square as shown.

Figure: http://i131.photobucket.com/albums/p289/SoaringCrane/Tip24_fig2.gif

When the electric field and the electric potential V are determined at P, the center of the square, we find that

a. E no equal 0; V>0

b. E = 0; V = 0

c. E = 0; V>0

d. E no equal 0; V<0

2. Relevant equations

See below.

3. The attempt at a solution

Well, if the vectors are drawn from the center, they cancel out so E = 0. If E=0, then wouldnâ€™t the potential also be 0?

Thanks.

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# Electric Potential and Electric Field

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