Electric potential at the bottom of a ring?

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SUMMARY

The discussion focuses on calculating the electric potential at a point located at the bottom of a circular ring with radius "a" and total charge "Q" uniformly distributed along the top half. The potential V at the observation point, defined by the angle φ from the positive x-axis, is derived using the equation V = k ∫ dq / r. Participants emphasized the need to express the differential charge dq in terms of the angle dθ and to apply trigonometric relationships to determine the distance r between dq and the observation point.

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Homework Statement


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A circular ring of radius "a" has a total charge Q uniformly distributed along the top half. (Q is distributed along the semicircle in quadrants I and II). What is the potential at a point located on the bottom of the ring (observation point is on the ring in quadrant III or IV). The location of the observation point is described as being located at an angle φ measured from the positive x axis. Find V(a,φ).

Homework Equations


[/B]
V = k ∫ dq / r
λ = dq/dL

The Attempt at a Solution


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So I substituted λdL for dq to get V = kλ ∫ dL / r but I'm not sure how to get r in terms of a and φ. I'm also not sure how just a semicircle of charge factors into this problem.
 

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Hi lz975545,

Welcome to Physics Forums!

You'll want to express dq in terms of dθ so that you can integrate over θ. For the distance between dq and the point of interest on the bottom half of the ring, think in terms of the distance between the points at the ends of the two radius vectors. So there'll be some trigonometry involved.
 

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