Electric Potential - Conceptual question

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Homework Help Overview

The discussion revolves around the concepts of electric potential and electric field in relation to a point charge. The original poster presents a scenario involving a specific electric field strength and electric potential, seeking to understand the implications of these values on the sign of the charge.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to explore the relationship between electric field and electric potential, specifically questioning the visual concept behind the sign of the charge when derived from the electric field. Other participants engage by discussing the limitations of determining the charge's sign solely from the electric field without additional directional information.

Discussion Status

The discussion is active, with participants verifying the implications of the given potential on the charge's sign. There is acknowledgment that the negative potential suggests a negative charge, although the original poster seeks deeper understanding of the underlying concepts.

Contextual Notes

Participants note that the direction of the electric field is not provided, which is crucial for determining the sign of the charge based solely on the electric field value.

EngineerHead
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Homework Statement



At a certain distance from a point charge, the magnitude of the electric field is 500 V/m and the electric potential is -3.00 kV. (a) What is the distance to the charge? (b) What is the magnitude of the charge?

Homework Equations



The Attempt at a Solution



a) 6 meters
b) -2 micro-Coulombs
*These are correct, I mention this fact cause I don't want you to have to waste your time checking so.

My question is: for part b, if you solve for Q, the magnitude of charge, from E instead of V (E = kq/r^2), what is the visual concept behind why the charge is negative? Because obviously if you solve from V, you will get a negative 2 uC.

Of course the book asks for magnitude anyway, but the answer key gives the negative sign as well. I want to understand the concept behind it.
 
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EngineerHead said:
My question is: for part b, if you solve for Q, the magnitude of charge, from E instead of V (E = kq/r^2), what is the visual concept behind why the charge is negative?
You cannot tell the sign of Q just using E, since you were not told the direction of the field.
 
Thank you, and just to verify - because of the potential given, it is a fact that the charge is negative?
 
EngineerHead said:
Thank you, and just to verify - because of the potential given, it is a fact that the charge is negative?
Yes.
 

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