Electric Potential Energy of electron orbits

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Homework Help Overview

The discussion revolves around the electric potential energy change when an electron and a proton are brought together to form a hydrogen atom, specifically focusing on the calculation of EPEfinal - EPEinitial.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for electric potential energy and express uncertainty about how to apply it. Some mention the potential energy at infinity being zero and question the implications of this for their calculations. Others refer to their notes on the relationship between charge and potential difference.

Discussion Status

There is ongoing exploration of the concepts involved, with participants sharing their thoughts and calculations. Some have attempted to apply formulas, while others are still trying to understand the underlying principles. Guidance has been offered regarding the use of charge values and constants in the calculations.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct assistance they can receive. There is also a focus on ensuring the correct application of constants and units in their calculations.

nckaytee
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An electron and a proton are initially very far apart (effectively an infinite distance apart). They are then brought together to form a hydrogen atom, in which the electron orbits the proton at an average distance of 5.43 * 10-11 m. What is EPEfinal - EPEinitial, which is the change in the electric potential energy?

I have no idea where to start
 
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nckaytee said:
An electron and a proton are initially very far apart (effectively an infinite distance apart). They are then brought together to form a hydrogen atom, in which the electron orbits the proton at an average distance of 5.43 * 10-11 m. What is EPEfinal - EPEinitial, which is the change in the electric potential energy?

I have no idea where to start

Isn't the potential energy given by PE = kq1*q2/r

If EPE at infinity is 0, then ... The change is ...
 
In my notes I have [tex]\Delta E.P.E[/tex] of electron = q(Vb-Va) = (-e)(Vb-Va)

I am really not getting this


Im sorry, I might have something here... One minute..
 
Okay I am confused
 
nckaytee said:
In my notes I have [tex]\Delta E.P.E[/tex] of electron = q(Vb-Va) = (-e)(Vb-Va)

I am really not getting thisIm sorry, I might have something here... One minute..

What is the charge of an electron and a proton?

Wikipedia said:
e = –1.602176487(40) × 10–19C
p = 1.60217653(14)×10−19 C
 
Last edited:
So, would it be...

(-1.6*10^19)(0 - 5.43 *10^-11)
 
nckaytee said:
So, would it be...

(-1.6*10^19)(0 - 5.43 *10^-11)

It's the product of both charges.

PE = kq1*q2/rAnd check the exponent of the charges. And don't forget k.
 
Okay, so I did PE = [(9*10^9)(-1.6*10^-19)(1.6*10^-19)] / 5.43*10^-11

My answer is right! -4.24 * 10^18

Thank you
 
nckaytee said:
Okay, so I did PE = [(9*10^9)(-1.6*10^-19)(1.6*10^-19)] / 5.43*10^-11

My answer is right! -4.24 * 10^18

Thank you

You're welcome.

And don't act so surprised. You had it nailed from kqq/r.

Good luck.
 

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