Electric potential homework problems

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SUMMARY

The discussion centers on the calculation of electric field strength based on a decrease in electric potential from 120V to 80V along the X-axis between x=-1cm and x=1cm. The correct answers for the electric field at the origin are options b) and c), indicating that it may equal or exceed 20V/cm, depending on the shape of the V vs. x graph. The reasoning provided clarifies that option a) is incorrect due to its definitive nature, which contradicts the variability of the electric field based on the graph's slope. The user is advised to consider different scenarios for the potential graph to understand the electric field's behavior.

PREREQUISITES
  • Understanding of electric potential and electric field concepts
  • Familiarity with V vs. x graph analysis
  • Knowledge of calculus, specifically derivatives for slope interpretation
  • Basic principles of electrostatics
NEXT STEPS
  • Study the relationship between electric potential and electric field using the formula E = -dV/dx
  • Explore different shapes of V vs. x graphs and their implications on electric field strength
  • Learn about the significance of concave and convex graphs in physics
  • Investigate real-world applications of electric fields in electrostatics
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric potential and field relationships.

gandharva_23
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mark the correct alternative :
The electric potential decreases from 120V to 80V as one moves on the X axis from x=-1cm to x=1cm . The electric field at the origin
a) must be equal to 20V/cm
b) may be equal to 20V/cm
c) may be greater than 20V/cm
d) may be greater than 20V/cm
i think all a , b and c should be correct but the answer given in the book is b and c . it will be b or c depending upon whether the V vs x graph is concave or convex . and b option will be correct for straight line graph .
what is incorrect in my approach ?
 
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gandharva_23 said:
mark the correct alternative :
The electric potential decreases from 120V to 80V as one moves on the X axis from x=-1cm to x=1cm . The electric field at the origin
a) must be equal to 20V/cm
b) may be equal to 20V/cm
c) may be greater than 20V/cm
d) may be greater than 20V/cm
i think all a , b and c should be correct but the answer given in the book is b and c . it will be b or c depending upon whether the V vs x graph is concave or convex . and b option will be correct for straight line graph .
what is incorrect in my approach ?

"a" can't be correct because of the "must be". If a was right, it would imply that this is the *only* possible answer (so it would not make sense to have a and another choice!).
 
Hi gandharva,

Simply knowing that the potential is decreasing from x = -1 to x = 1 is not nearly enough information to tell you what the electric field is at x = 0. All you know is that its positive since the potential is said to be decreasing. Try imagining or drawing situations where the slope of the potential graph is very small or very great at x = 0. See what possibilities you can come up with, and remember, the potential can do anything as long its decreasing the whole time.

Hope this helps.

P.S. As you have written it, the answer d) is the same as c). You might check to make sure you have posted all the information correctly.
 

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