Electric Potential Inside a Parallel-Plate Capacitor

  • #1
Thank you for taking the time to look. I think I get the basic idea here but I'm must be missing something important. Any help is greatly appreciated.

Homework Statement

Two 1.4g beads, each charged to 5.1nC , are 2.2cm apart. A 2.8g bead charged to -1.0nC is exactly halfway between them. The beads are released from rest.

What is the speed of the positive beads, in cm/s, when they are very far apart?
Express your answer using two significant figures.

Homework Equations


The Attempt at a Solution

[tex]m_{1}=0.0014 kg[/tex]
[tex]m_{2}=0.0014 kg[/tex]
[tex]m_{3}=0.0028 kg[/tex]
[tex]q_{1}=5.1*10^{-9} C[/tex]
[tex]q_{2}=5.1*10^{-9} C[/tex]
[tex]q_{3}=-1*10^{-9} C[/tex]
[tex]r_{12}=0.022 m[/tex]
[tex]r_{13}=0.011 m[/tex]

[tex]K_{i}=0[/tex] because initial velocity of all three is 0
[tex]U_{f}=0[/tex] because they end far apart --> r->[tex]\infty[/tex]

So [tex]U_{i}=K_{f}[/tex]

[tex]\Longrightarrow\sqrt\frac{2}{4\pi\epsilon_{0}m_{1}}\{\frac{q_{1}q_{2}}{r_{12}}+\frac{q_{1}q_{3}}{r_{13}}\}}[/tex] (the sqrt sgn should extend to the end of the expression but I suck as LaTeX)
  • #2
got it now.

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