Electric potential problem. Conceptual.

Click For Summary
SUMMARY

The discussion centers on calculating the electric potential difference experienced by an electron moving from the origin to the point x=2, where its speed decreases from V1 to V2 (V2 PREREQUISITES

  • Understanding of electric potential and electric fields
  • Knowledge of the behavior of charged particles in electric fields
  • Familiarity with the concepts of kinetic energy and potential energy
  • Basic principles of classical mechanics
NEXT STEPS
  • Study the relationship between electric potential and electric fields in detail
  • Explore the motion of charged particles in uniform electric fields
  • Learn about the conservation of energy in electric fields
  • Investigate the effects of different charge types on electric potential
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of electric potential and the behavior of charged particles in electric fields.

haydn
Messages
26
Reaction score
0
Problem: An electron moving parallel to the x-axis has an initial speed of V1 at the origin. It's speed is reduced to V2 at the point x=2 (V2<V1). Calculate the potential difference between the origin and the point x=2. Which point is at the higher potential?

I was able to calculate the potential difference pretty easily but I got the second part wrong. I thought the higher potential would be at the point x=2 but the book says the origin. Here is my reasoning, please tell me where I'm going wrong:

Since the electron is decelerating along the positive x-axis, it is experiencing a force due to an electric field pointing in the -x direction. Since electric potential decreases as you move along the direction of an electric field, the origin should be at lower potential.

Thanks.
 
Physics news on Phys.org
Hi haydn! :smile:
haydn said:
Since the electron is decelerating along the positive x-axis, it is experiencing a force due to an electric field pointing in the -x direction. Since electric potential decreases as you move along the direction of an electric field, the origin should be at lower potential.

hmm :rolleyes: … would this be one of those negatively charged electrons? :wink:
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
764
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K