Electric Potential Produced by Point Charge

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Homework Help Overview

The discussion revolves around calculating the electric potential produced by a point charge of -8 µC located at the origin, specifically at three different points in a Cartesian coordinate system.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of the formula for electric potential and question the correct distance (r) to use for the third point in the Cartesian plane.

Discussion Status

Some participants have provided guidance on interpreting the coordinate system, particularly regarding the calculation of the distance r for the third point. There is an acknowledgment of misunderstanding regarding the coordinates and their implications.

Contextual Notes

Participants are grappling with the interpretation of Cartesian coordinates and how they relate to the calculation of distance in the context of electric potential.

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Homework Statement



A point charge of -8 µC is at the origin. What is the electric potential at
(a) (3.0m, 0),
(b) (-3.0m, 0), and
(c) (3.0m, -3.0m)?




Homework Equations



V=kq/r


The Attempt at a Solution



a & b) V=(8.99x10^9)(-8x10^-6)/3
V= -23973.3

c) V=(8.99x10^9(-8x10^-6)/6



I understand part a and b and got the correct answer. However, for part c, the only thing I am doing different is r=6 instead of 3 because the coordinates are (3.0m, -3.0m) and I am not getting the correct answer. I don't really understand. Thank you.
 
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r does not equal 6. Think about the coordinate system.
 
I thought r=6 because there is 3 in the + x direction and 3 in the -x direction on either side of the origin (x=0) so I added them to get a total of 6 from -x to +x. I'm not really sure how to look at the coordinate system any other way?
 
The two numbers denote the x and y coordinates in a cartesian plane. How can you have a position with two x coordinates? Draw the x an y axes and work out what r should be for the (3, -3) point.
 
ohhhh wow I'm so blind. Thank you very much for your help!
 

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