Electric potential, solution to Laplace's Eq.

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SUMMARY

The discussion centers on proving that the electric potential outside a radially symmetric charge distribution, defined as V = q/(4*pi*epsilon_0*r), satisfies Laplace's Equation. The approach suggested involves demonstrating that the second derivative of V with respect to the radial coordinate r results in zero, confirming that V is indeed a solution to Laplace's Equation. Participants emphasize the efficiency of this method over directly solving Laplace's Equation.

PREREQUISITES
  • Understanding of electric potential and charge distributions
  • Familiarity with Laplace's Equation and its significance in electrostatics
  • Knowledge of spherical coordinates and their application in vector calculus
  • Proficiency in taking derivatives, particularly second derivatives
NEXT STEPS
  • Review the derivation of the Laplacian in spherical coordinates
  • Study the properties of radially symmetric charge distributions
  • Explore applications of Laplace's Equation in electrostatics
  • Learn about boundary conditions and their role in solving differential equations
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism and mathematical methods in physics, will benefit from this discussion.

nsatya
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Homework Statement



Prove that the potential outside of any radially symmetric charge distribution of total charge q, given by,

V = q/(4*pi*epsilon_0*r)

is a solution to Laplace's Equation.

Hint: Only a masochist would solve this problem by solving Laplace's Equation. It is much easier to demonstrate that this solution is a solution to Laplace's equation.



Homework Equations





The Attempt at a Solution



I first tried to plug V into Laplace's Equation del^2 V = 0. Since V only depends on r in this case, I thought I could just take the 2nd derivative of V and show that it is 0. I got to this point but could not go much further with it. Any help would be appreciated.
 
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Hint: what is the Laplacian of any scalar function [tex]f[/tex] in spherical coordinates? Is the radial component really just [tex]\frac{\partial^2 f}{\partial r^2}[/tex] ? :wink:
 

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