Finding potential for a sphere, when to use laplace equation

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Homework Help Overview

The problem involves finding the electric potential inside and outside a spherical shell with a specified surface charge density, σ(θ), as presented in Griffiths Electrodynamics. The discussion centers around the use of Laplace's equation versus Gauss' law for solving the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the appropriateness of using Laplace's equation for this problem, questioning why it is favored over Gauss' law. There is discussion about the implications of the charge distribution and the resulting electric field.

Discussion Status

The discussion is active, with participants sharing their reasoning and questioning assumptions about the applicability of different methods. Some have successfully used Laplace's equation, while others are exploring alternative approaches and clarifying misunderstandings regarding Gauss' law.

Contextual Notes

Participants note the specific charge distribution given in the problem and the implications it has on the calculations. There is mention of the symmetry of the problem and the resulting electric field characteristics, which are under scrutiny.

cshanny
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Homework Statement


This is example 3.9 in Griffiths Electrodynamics.
"A specified charge density σ(θ) (inclination angle) is glued over the surface of a spherical shell of radius R. Find the resulting potential inside and outside the sphere." The problem suggests that although it is possible to compute this by using the integral for potential V=(1/4πε)int[σ(θ)dA], it is much easier to do so by separation of variables.[/B]

Homework Equations


The solution to this example uses separation of variables, using the general solution to Laplace's equation in spherical coordinates.

The Attempt at a Solution


At the suggestion of the book, I correctly found the potential inside and outside of the sphere using the Laplace equation. My question is what in the problem signifies that this is most easily solved with Laplace equation and not, say, Gauss' law. I could certainly say that because the charge is on the surface of the sphere that the electric field inside is 0 and therefore the potential is constant. I could also find the electric field outside by integrating the charge density to find the total enclosed charge outside of the sphere (which yields zero...). I'm obviously missing something here.
 
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The enclosed charge for a gaussian surface outside the sphere is not zero, it is the total charge of the sphere. This way you would have to argue by symmetry that the electric field must be radial and integrate to find the potential.
 
Sorry I left something out in my post. They actually give the charge distribution as kcosθ...so I calculated Qenclosed by integrating the charge density over the surface of the sphere. The fact that there's a sinθcosθ in the integral made it go to zero.

Also, I don't quite understand why Gauss' law is not applicable.
 
Gauss law is applicable. Your assumption that the field is purely radial and constant is not.
 
Got it. How else can I approach this problem?
 
What was wrong with solving the Laplace equation?
 
Posting again to make sure you see it rather than miss my edit.

Of course, there are different methods available to solve the Laplace equation. One of them would be to integrate to sum up the contributions from each part of the surface. (Aka, Green's function methods)
 
Nothing it worked just fine and I got the correct answer. I was just curious if there was any other obvious way of doing this.
 

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