Two positive charges, each with Q = +12 µC, are fixed to the x-axis at x = +a and x = -a, where a = 2 m.
Part A was not a poblem to find.
(a) Find the electric potential at point A on the y-axis where (xA, yA) = (0, b) and b = 5 m. Take the zero of potential to be at infinity.
V(A) = 40065.62617V
(b) A particle with charge q = -6 µC and mass m = 1.5 x 10-4 kg is released from rest at point A. Find its speed at the origin.
V at the origin = ???
V(a)-V(b) = ∫E•dl = kQ/r
w = 0.5*m*(v1^2 - v0^2) = F•d
potential energy = kq1q2/r
3. The Attempt at a Solution
I think I have the equations I need for this problem. For this problem do I need to find a way to relate work to the potential energy?