Electric potential with charges

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Homework Help Overview

The problem involves two charges placed at the corners of a square, specifically a +4.0 µC charge and a -6.0 µC charge. The objective is to determine what charge must be placed at the intersection of the diagonals to achieve a zero potential difference at the two unoccupied corners of the square.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of using the formula for electric potential and question the validity of assuming an infinite distance for the radius in the context of potential difference. There are suggestions to express the side length of the square as a variable and to calculate the potential at the corners based on the distances from the charges.

Discussion Status

Some participants have provided guidance on how to approach the problem by suggesting the use of variable side lengths and the need to consider the electric field produced by the charges. There is an acknowledgment of the need to set the sum of the electric fields to zero to find the unknown charge.

Contextual Notes

Participants are exploring the relationships between the charges and their positions, as well as the implications of the potential difference in the context of the square's geometry. There is an emphasis on using variables to represent distances rather than assuming infinite values.

canadianballa
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Homework Statement


Two charges are placed at the corners of a square. One charge, +4.0uC, is fixed to one corner and another, -6.0uC is fixed to the opposite corner. WHat charge would need to be placed at hte intersection of the diagonals of the square in order ot make the potential difference zero at each of the two unoccupied corners?


Homework Equations


V = kq/r


The Attempt at a Solution


Given that potential difference (or voltage) is calculated based on the formula above, can I just assume that the radius of this square is infinitely large and therefore V becomes zero and that the charge is some number that is much smaller than infinite?
I'm not sure if I'm allowed to do this. Please help.
 
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Hi Canadianballa,

canadianballa said:

Homework Statement


Two charges are placed at the corners of a square. One charge, +4.0uC, is fixed to one corner and another, -6.0uC is fixed to the opposite corner. WHat charge would need to be placed at hte intersection of the diagonals of the square in order ot make the potential difference zero at each of the two unoccupied corners?


Homework Equations


V = kq/r


The Attempt at a Solution


Given that potential difference (or voltage) is calculated based on the formula above, can I just assume that the radius of this square is infinitely large and therefore V becomes zero and that the charge is some number that is much smaller than infinite?
I'm not sure if I'm allowed to do this. Please help.

No, I don't think that's what they want you to do here. Instead, let the side length of the square be some unknown distance d. If the side has length d, what is the potential from each of the three charges (4 uC, -6uC, and Q) at one of the unoccupied corners (using your equation)? (You'll need to find the distance, in terms of d, that each of the three charges is from the corner.) If the sum of those three terms has to be zero, then that will give you the unknown charge Q.
 
Let the side of the sqaure be s. Place one known charge on the y axis, the other on the x-axis of a coordinate system, and the unknown charge at the intersection of the square diaganols. V = Ed where E is the electric field produced by the point charge and d is the distance from the point charge. A zero potential exists when no net electric field is present. So, use the expression for determining the electric field at a square corner by the point charges of the two known and one unknown charges and solve for the unkown charge by setting the vector sum of the three electric fields equal to zero. Your answer will be in terms of s.
 
Thanks guys for your help. I'll work on solving it now and post the attempt in a bit.
 

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