Electrical Charges and Attraction

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Homework Help Overview

The discussion revolves around the interaction between two electrical charges of the same type (negative) but with different voltages, specifically -600VDC and -100VDC. The original poster expresses confusion regarding the attraction or repulsion of these charges, referencing a source that suggests they would attract.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of charge and voltage, questioning the original poster's understanding of how voltage relates to charge interactions. Some suggest that the terminology used in the original source may be misleading.

Discussion Status

Participants are engaged in clarifying concepts related to electrical charges and voltages. There is an ongoing examination of the original poster's source material, with some guidance provided regarding the distinction between charge and voltage. Multiple interpretations of the source's wording are being explored.

Contextual Notes

The original poster references a specific context involving a metallic roller in an electrophotographic process, which introduces additional complexities regarding charge interactions and definitions. There is a request for clarification on the terminology used in the source material.

csfyp.mail
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Hi, Pls I'd like to find out if 2 electrical charges (same charge but different voltages) would attract or repel. For example -600VDC and -100VDC.

I've always thought like charges repel and unlike charges attract. But I'm reading up on something that says the above would attract and become -600VDC.

Pls can someone explain why this is the case. Thanks
 
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csfyp.mail said:
Hi, Pls I'd like to find out if 2 electrical charges (same charge but different voltages) would attract or repel. For example -600VDC and -100VDC.

I've always thought like charges repel and unlike charges attract. But I'm reading up on something that says the above would attract and become -600VDC.

Pls can someone explain why this is the case. Thanks

Welcome to the PF.

Charges do not have "voltage" as you have written. Charges are measured in units of Coulombs, and the electric fields that they cause will be the origin in changes in voltage (electrical potential).

Can you please copy the exact wording and figure from your textbook that have you confused?
 
berkeman said:
Welcome to the PF.

Charges do not have "voltage" as you have written. Charges are measured in units of Coulombs, and the electric fields that they cause will be the origin in changes in voltage (electrical potential).

Can you please copy the exact wording and figure from your textbook that have you confused?


This is it...

"A metallic roller called the developing roller inside an EP cartridge acquires a – 600VDC charge (called a bias voltage) from the HVPS. The toner sticks to this roller because there is a magnet located inside the roller and because of the electrostatic charges between the toner and the developing roller. While the developing roller rotates toward the photo-sensitive drum, the toner acquires the charge of the roller (–600VDC). When the toner comes between the developing roller and the photosensitive drum, the toner is attracted to the areas that have been exposed by the laser (because these areas have a lesser charge, –100VDC). The toner also is repelled from the unexposed areas (because they are at the same –600VDC charge, and like charges repel)."


EP - Electrophotographic
HVPS - High Voltage Power Supply

Thanks
 
csfyp.mail said:
This is it...

"A metallic roller called the developing roller inside an EP cartridge acquires a – 600VDC charge (called a bias voltage) from the HVPS. The toner sticks to this roller because there is a magnet located inside the roller and because of the electrostatic charges between the toner and the developing roller. While the developing roller rotates toward the photo-sensitive drum, the toner acquires the charge of the roller (–600VDC). When the toner comes between the developing roller and the photosensitive drum, the toner is attracted to the areas that have been exposed by the laser (because these areas have a lesser charge, –100VDC). The toner also is repelled from the unexposed areas (because they are at the same –600VDC charge, and like charges repel)."


EP - Electrophotographic
HVPS - High Voltage Power Supply

Thanks

Ah, that makes more sense. They are using the word "charged" in the context of charging up the capacitances of the roller and drum. The charge on a capacitor is Q = C*V, where C is the capacitance, and V is the voltage.

The explanation is not very precisely worded, unfortunately. The explanation at wikipedia.org is better:

http://en.wikipedia.org/wiki/Photocopier

.
 
Alright, Thanks.
 

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