Electrical field outside spherical shell

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SUMMARY

The discussion centers on calculating the electric field outside an insulated spherical shell with a surface charge density defined as \(\sigma(\theta) = \sigma_0 \sin(\theta)\). The total charge \(Q\) on the shell is determined to be \(\pi^2 R^2 \sigma_0\) using integration over the surface. However, the participant expresses uncertainty about applying Gauss's Law to find the electric field at the point \(z=R\). The suggestion to calculate \(\int \frac{dq}{r^2}\) indicates a search for an alternative method to derive the electric field.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with spherical coordinates and surface charge density
  • Ability to perform integrals over spherical surfaces
  • Knowledge of electric field concepts and calculations
NEXT STEPS
  • Review the application of Gauss's Law for non-uniform charge distributions
  • Study the derivation of electric fields from surface charge densities
  • Learn about the method of integrating charge distributions in spherical coordinates
  • Explore the concept of electric fields due to dipole distributions
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying electromagnetism, as well as educators and anyone seeking to deepen their understanding of electric fields generated by non-uniform charge distributions.

glederfein
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Homework Statement


An insulated spherical shell with its center in the origin and radius R has a surface charge density of \sigma(\theta)=\sigma_0\sin(\theta) when \theta is the angle from the z axis. Calculate the electrical field outside the shell at point z=R.


Homework Equations



Gauss's Law
\int\int{\vec{E}\cdot\vec{dS}}=4\pi{Q_{in}}


The Attempt at a Solution



I tried first calculating the overall charge of the spherical shell:
Q=R^2\int_0^{2\pi}\sigma_0\sin^2\theta{d\theta}\int_0^\pi{d\phi}=\frac{R^2\sigma_0}{2}\int_0^{2\pi}(1-\cos{2\theta})d\theta\cdot\pi=\frac{1}{2}\pi{R^2}\sigma_0\cdot{2\pi}=\pi^2R^2\sigma_0
However, I don't see how Gauss's Law can help me find the electrical field at that specific point.

Please help!
 
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anyone?

Can someone please help??

Perhaps I should somehow calculate \int{\frac{dq}{r^2}} ?
 

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