[Electrical force] 2 balls hanging from ceiling, angled

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The discussion focuses on the calculation of electric force between two balls hanging from a ceiling, addressing the incorrect use of the tangent function in the initial formula. Participants clarify that the electric force is determined by the horizontal component of tension, while weight corresponds to the vertical component. They derive equations balancing forces in both horizontal and vertical directions, ultimately leading to expressions for tension and electric force. The correct relationship involving the angle of 10 degrees is emphasized, with a consensus on using sine rather than tangent for calculations. The conversation concludes with a confirmation of the correct expression for the distance between the balls.
  • #31
sea333 said:
I still don't see how this is correct as angle 10 is not adjacent to r
Draw a vertical line down from the apex and consider the two triangles produced.
 
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  • #32
I don't think I will need these advance techniques in my exercises
 
  • #33
sea333 said:
I don't think I will need these advance techniques in my exercises
Dropping a perpendicular from the apex of an isosceles triangle to create two congruent right angled triangles is pretty basic geometry; less advanced, even, than the cosine rule.
 
  • #34
haruspex said:
Dropping a perpendicular from the apex of an isosceles triangle to create two congruent right angled triangles is pretty basic geometry; less advanced, even, than the cosine rule.
I have checked this and I get r = 2a*sin10
 
  • #35
sea333 said:
I have checked this and I get r = 2a*sin10
Yes, as in my correction in post #27.
 
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  • #36
sea333 said:
sqrt(4a^2sin^2(10)) = 2*a*sin10

How do you get from 1 - cos^2(10) - sin^2(10) to 2 sin^2(10) ?
1 - cos^2(10) + sin^2(10) = 2sin^10 because cos^2(10) + sin^2(10) = 1
 

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