[Electrical force] 2 balls hanging from ceiling, angled

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    Balls Force
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Homework Help Overview

The discussion revolves around the forces acting on two balls hanging from a ceiling at an angle, specifically focusing on the relationship between electric force, tension, and gravitational force. Participants are exploring the balance of forces in both horizontal and vertical directions, as well as the implications of the angle formed by the strings.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to derive equations for the forces acting on the balls, questioning the correctness of initial expressions and exploring the relationships between tension, electric force, and gravitational force. There is also discussion on how to incorporate the angle of the strings into their equations.

Discussion Status

The discussion is active, with participants providing guidance on how to set up equations and questioning assumptions made in earlier posts. There is an ongoing exploration of the relationships between different forces and the geometry of the setup, with no clear consensus reached yet.

Contextual Notes

Some participants note the need to use symbols instead of numerical values in their equations and emphasize the importance of correctly applying trigonometric relationships to the problem. There are also mentions of potential errors in previous attempts, particularly regarding the use of angles in calculations.

  • #31
sea333 said:
I still don't see how this is correct as angle 10 is not adjacent to r
Draw a vertical line down from the apex and consider the two triangles produced.
 
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  • #32
I don't think I will need these advance techniques in my exercises
 
  • #33
sea333 said:
I don't think I will need these advance techniques in my exercises
Dropping a perpendicular from the apex of an isosceles triangle to create two congruent right angled triangles is pretty basic geometry; less advanced, even, than the cosine rule.
 
  • #34
haruspex said:
Dropping a perpendicular from the apex of an isosceles triangle to create two congruent right angled triangles is pretty basic geometry; less advanced, even, than the cosine rule.
I have checked this and I get r = 2a*sin10
 
  • #35
sea333 said:
I have checked this and I get r = 2a*sin10
Yes, as in my correction in post #27.
 
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  • #36
sea333 said:
sqrt(4a^2sin^2(10)) = 2*a*sin10

How do you get from 1 - cos^2(10) - sin^2(10) to 2 sin^2(10) ?
1 - cos^2(10) + sin^2(10) = 2sin^10 because cos^2(10) + sin^2(10) = 1
 

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