[Electrical force] 2 balls hanging from ceiling, angled

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SUMMARY

The discussion centers on the calculation of electric force between two charged balls hanging from a ceiling at a 10-degree angle. The correct expression for the electric force is derived from balancing horizontal and vertical forces, leading to the equations T = mg / cos(10°) and Fx = (1/(4πEps0))(q²/r²). The participants clarify that the angle affects the relationship between tension and electric force, ultimately leading to the correct expression for r as r = 2a sin(10°). Missteps in using tangent instead of sine for angle-related calculations are also addressed.

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  • #31
sea333 said:
I still don't see how this is correct as angle 10 is not adjacent to r
Draw a vertical line down from the apex and consider the two triangles produced.
 
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  • #32
I don't think I will need these advance techniques in my exercises
 
  • #33
sea333 said:
I don't think I will need these advance techniques in my exercises
Dropping a perpendicular from the apex of an isosceles triangle to create two congruent right angled triangles is pretty basic geometry; less advanced, even, than the cosine rule.
 
  • #34
haruspex said:
Dropping a perpendicular from the apex of an isosceles triangle to create two congruent right angled triangles is pretty basic geometry; less advanced, even, than the cosine rule.
I have checked this and I get r = 2a*sin10
 
  • #35
sea333 said:
I have checked this and I get r = 2a*sin10
Yes, as in my correction in post #27.
 
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  • #36
sea333 said:
sqrt(4a^2sin^2(10)) = 2*a*sin10

How do you get from 1 - cos^2(10) - sin^2(10) to 2 sin^2(10) ?
1 - cos^2(10) + sin^2(10) = 2sin^10 because cos^2(10) + sin^2(10) = 1
 

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