Two pith balls, each with a mass of 5.00g, are attached to non-conducting threads and suspended from the same point on the ceiling. Each thread has a length of 1.00m. The balls are then given an identical charge, which causes them to separate. At the point that the electrical and gravitational forces balance, the threads are separated by an angle of 30.0 degrees. Calculate the charge on each pith ball." My answer isn't matching the text books of 6.27 x 10^-7 C Relevant Equations: Fg=Gm1m2/r^2 Fe=kq1q1/r^2 Attempt: (G)(m)^2/r^2=(k)(q)^2/r^2 r^2 cancels out G(m)^2=k(q)^2 root [(G)(m)^2]/k =4.3 x 10^-13 Am i missing something? Or is the book wrong?