Electrolysis of Water: How Rheostat Affects Bubbles Produced

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Discussion Overview

The discussion revolves around the electrolysis of water, specifically examining how the use of a rheostat affects the production of gas bubbles during the process. Participants explore the relationship between electrical resistance, current, voltage, and gas production, as well as the implications of power changes in a constant-voltage circuit.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant observes that increasing the resistance of the rheostat leads to a decrease in the number of bubbles produced per second during electrolysis.
  • Another participant prompts for consideration of how changing resistance affects other electrical quantities in a constant-voltage circuit, specifically questioning the relationship between current and bubble production.
  • A participant connects the decrease in current to the decrease in bubble production, suggesting that current is related to the number of electrons and thus the formation of gas bubbles.
  • There is a discussion about the constancy of voltage from a battery and how it relates to power and resistance in the circuit.
  • One participant expresses confusion about how to maintain constant voltage while varying power, indicating a need for clarification on battery behavior.
  • Another participant explains that a battery provides constant voltage over a range of currents, emphasizing that the relevant quantity affecting bubble production is the current, which decreases with increased resistance.
  • Questions arise about the possibility of changing the voltage of the battery and the implications of voltage drops in a circuit with resistances in series.
  • One participant raises a question about the fate of excess power input when gas production remains constant, speculating on the conversion of excess power into heat and its effects on the electrolyte.
  • Another participant reiterates the idea that heat from resistance may cause some liquid to evaporate, leading to condensation in the gas storage cylinder.
  • A participant inquires about the appropriate voltage for using 1 molar sulfuric acid in electrolysis and how to maintain the concentration of the acid.

Areas of Agreement / Disagreement

Participants express various viewpoints regarding the relationship between resistance, current, and gas production, with no clear consensus reached on all aspects of the discussion. Some participants agree on the constancy of battery voltage, while others question its implications. The discussion remains unresolved regarding the effects of excess power input and the specifics of maintaining acid concentration.

Contextual Notes

Participants discuss the behavior of batteries in circuits, the relationship between resistance and current, and the implications for gas production during electrolysis, but there are unresolved questions about the effects of excess power and maintaining chemical concentrations.

chanller
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While doing electrolysis of water, I have put a rheostat and a battery in series with the apparatus. I found that when I increase the resistance of the rheostat, the number of bubbles produced per second decreases. How can you explain that?
 
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Before we can respond, we need to see what you think. Do you have any idea what other electrical quantities are affected by changing the resistance in a constant-voltage circuit? And the bubbles - what physical quantity do they relate to?
 
If the power withdrawn from a battery depends on the resistance of the circuit, then i guess current changes if P=IV. But, how can you keep the voltage from a battery constant while varying power withdrawn?
 
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Yes, that's correct, though it actually follows more directly from Ohm's Law, V=IR. So, does the current increase or decrease?
 
I believe current for the electrolysis decreases if the voltage is constant and if current = electrons and electrons= gas bubbles, current decreases. Is it that when i increase resistance of the rheostat, power through it increases and that through the electrolysis decreases? This would explain why gas flow decreases but then it would mean power from the battery is constant! But, how can you keep the voltage from a battery constant while varying power withdrawn?
 
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There is no need to worry about power here. A bettery is, by definition, a device which produces a constant voltage over a large range of currents. The power dropped (both at the rheostat and at the cell) decreases as you increase the resistance (because the current decreases, while the voltage is constant) but that's not the relevant quantity here. The relevant quantity is the current, which decreases.

As you mentioned, the current is simply the rate at which electrons are transferred between the electrodes. Each pair of electrons arriving at the cathode makes a molecule of hydrogen gas form there. The slower the rate of electrons, the slower will be the rate of hydrogen bubble formation.
 
Well, what I did not know is that voltage from a battery is constant; now everything is clear! But can the voltage be changed and if yes, how?
 
The battery represents the maximum allowable voltage, and then there is a voltage drop proportional to resisance and current.

Two resistance in series represent a voltage divider.
 
I finally had to leaf through my physics book. Well I learned that physics was not just theory which I have to learn by heart! Thanks everyone!
 
  • #10
Talking about electrolysis, what happens to the excess power input when gas production rate remains constant even though power is increased? Droplets of water settled at the top of my gas storage cylinder, does this mean excess power is converted into heat which vaporises water in the electrolyte?
 
  • #11
chanller said:
Talking about electrolysis, what happens to the excess power input when gas production rate remains constant even though power is increased? Droplets of water settled at the top of my gas storage cylinder, does this mean excess power is converted into heat which vaporises water in the electrolyte?
There is heat involved from resistance, and the heat will cause some liquid to evaporate which would condense on a cooler surface.
 
  • #12
If i use 1 molar sulphuric acid at rtp what voltage do you think i should use? 1.5V will be good?

Also, how can i keep the concentration of the acid constant?
 

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